tìm x biết
x-6/15 - 6/63 - 6/99 - 6/143 - 6/195 = 1/5
TH
Những câu hỏi liên quan
A= 6/15 + 6/35 + 6/63 + 6/99 + 6/143 + 6/195 + 6/255 help
A=6/3.5 + 6/5.7 +....+ 6/15.17
A= 3(1/3-1/5+1/5-1/7+....+1/15-1/17)
A= 3(1/3-1/17)
A= 3.14/51
A=14/17
Vậy....
Đúng 1
Bình luận (0)
Tính:
a) 1/15+135+1/63+1/99+1/143+1/195+1/255+1/323
b) 1/2 x 6+1/4 x 9+ 1/ 6 x12 +.............. + 1/36 x 37+1/ 38 x 60
A=\(\dfrac{2}{3}\)+\(\dfrac{14}{15}\)+\(\dfrac{34}{35}\)+\(\dfrac{62}{63}\)+\(\dfrac{98}{99}\)+\(\dfrac{142}{143}\)+\(\dfrac{194}{195}\)
Và B=5+\(\dfrac{1}{2^2}\)+\(\dfrac{1}{3^3}\)+\(^{\dfrac{1}{4^4}}\)+\(\dfrac{1}{5^5}\)+\(\dfrac{1}{6^6}\)+\(\dfrac{1}{7^7}\).So sánh A và B
Bài 1 :So sánh
A= 2^19 .27^3+15.4^9.9^4/6^9.2^10+12^10 va B = 4/35+4/63+4/99+4/143+4/195
Bài 2 : tìm x biết :
60%.x+0,4.x +x:3=2
BÀI 2
60%.x + 0,4.x + x:3= 2
\(\frac{60}{100}\)x + \(\frac{4}{10}\).x + x. \(\frac{1}{3}\)=2
\(\frac{3}{5}\).x + \(\frac{2}{5}\).x + x.\(\frac{1}{3}\)=2
(\(\frac{3}{5}\)+ \(\frac{2}{5}\)+ \(\frac{1}{3}\)) .x =2
\(\frac{4}{3}\).x =2
x = 2: \(\frac{4}{3}\)
x = \(\frac{3}{2}\)
Vậy x=\(\frac{3}{2}\)
k cho mik nha các bạn
Đúng 0
Bình luận (0)
Bài 2 :
60%x + 0.4x + x : 3 = 2
\(x.\left(\frac{60}{100}+\frac{2}{5}+\frac{1}{3}\right)\)= 2
\(x.\frac{4}{3}\)= 2
\(x=2.\frac{3}{4}\)
\(x=1.5\)
Đúng 0
Bình luận (0)
a) Tính tổng S=\(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)
b) Tìm các số nguyên dương thỏa mãn
\(\frac{5}{a}-\frac{b}{3}=\frac{1}{6}\)
2S=\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}+\frac{2}{13.15}\)
= \(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{13}-\frac{1}{15}\)
=\(1-\frac{1}{15}=\frac{14}{15}\)
\(\Rightarrow S=\frac{7}{15}\)
Đúng 0
Bình luận (0)
a. Ta có:A= 1/1.3+1/3.5+1/5.7+1/7.9+1/9.11+1/11.13+1/13.15
A=1/2(1/1.3+1/3.5+1/5.7+1/7.9+1/9.11+1/11.13+1/13.15)
A=1/2(1/1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11+1/11-1/13+1/13-1/15)
A=2(1-1/15)
A=1/2.14/15
A=7/15
Đúng 0
Bình luận (0)
phần b nè
pt \(\Rightarrow90-6ab=3a\)\(\Leftrightarrow3a\left(b+2\right)=90\)vì b>0 \(\Leftrightarrow a=\frac{30}{b+2}\)mà a,b \(\inℕ^∗\)
\(\Rightarrow\)b+2\(\inƯ\left(30\right)\)MÀb\(\inℕ^∗\)\(b+2\in\left\{3;5;6;10;15;30\right\}\)khi đó tìm đc b \(\rightarrow\)thau vào tìm a . nhớ thử lại vào pt ban đầu nhé
k cho mk nha mn ^.^
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
Câu 1 : Thực hiện phép tính :
a) 1/3 + 1/15 + 1/35 + 1/63 + 1/99 + 1/143 + 1/195
b) 1414 + 1515 + 1616 + 1717 + 1818 + 1919 phần 2020 + 2121 + 2222 + 2323 + 2424 + 2525
Câu 2 :Tìm x biết :
1/3 + 1/6 + 1/10 +....+ 2/x(x+1) = 2011/2013
Câu 3:
So sánh hai số A và B biết :
A = 1.2 + 2.4 + 3.6 + 4.8 + 5.10 phần 3.4 + 6.8 + 9.12 + 12.16 + 15.20
B = 111111 phần 666665
Lục Minh Hoàng cho mình hỏi tại sao lại có 1/2 vậy ?
Đúng 0
Bình luận (0)
1/3+1/15+1/35+1/63+1/99+1/143+1/195
=1/1*3+1/3*5+1/5*7+1/7*9+1/9*11+1/11*13+1/13*15
suy ra 2(1/1*3+1/3*5+1/5*7+1/7*9+1/9*11+1/11*13+1/13*15)
=2/1*3+2/3*5+2/5*7+2/7*9+2/9*11+2/11*13+2/13*15
=1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11+1/11-1/13+1/13-1/15
=1-1/15
=14/15
a=14/15 chia 2=7/15
Đúng 0
Bình luận (0)
1,tính nhanh
a,1+3+5+7+9+....+2007++2009+2011x(125125x127+127127x125)
b,\(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)
2,Tìm \(x\)
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+....+\frac{2}{x\cdot\left(x+1\right)}=\frac{1011}{2013}\)
\(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)
\(=\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+...+\frac{1}{13\cdot15}\)
\(=\frac{1}{2}\left(\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{13\cdot15}\right)\)
\(=\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}\right)\)
\(=\frac{1}{2}\left(1-\frac{1}{15}\right)\)
\(=\frac{1}{2}\cdot\frac{14}{15}\)
\(=\frac{7}{15}\)
Đúng 0
Bình luận (0)
Sửa đề chút nhé:
\(\left(1+3+5+7+...+2009+2011\right).\left(125125.127-127127.125\right)\)
\(=\left(1+3+5+7+...+2009+2011\right).\left(125.1001.127-127.1001.125\right)\)
\(=\left(1+3+5+7+...+2009+2011\right).0\)
\(=0\)
Ý b tham khảo bài bạn nguyen thi thuy linh nhé
Đúng 0
Bình luận (0)
\(\text{Tính nhanh : }\)
\(a,\text{ }1+3+5+7+9+\text{...}+2007+2009+2011\cdot\left(125125\cdot127+127127\cdot125\right)\)
\(=\left\{\left(2009-1\right)\text{ : }2+1\right\}\cdot\left(2009+1\right)\text{ : }2+2011\cdot\left(125125\cdot127+127127\cdot125\right)\)
\(=1005\cdot2010\text{ : }2+2011\cdot\left(125125\cdot127+127127\cdot125\right)\)
\(=2020050\text{ : }2+2011\cdot\left(125125\cdot127+127127\cdot125\right)\)
\(=1010025+2011\cdot\left(125125\cdot127+127127\cdot125\right)\)
\(=1010025+2011\cdot\left(15890875+15890875\right)\)
\(=1010025+2011\cdot15890875\cdot2\)
\(=1010025+31956549625\cdot2\)
\(=1010025+63913099250\)
\(=63914109275\)
\(b,\text{ }\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)
\(=\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}+\frac{1}{9\cdot11}+\frac{1}{11\cdot13}+\frac{1}{13\cdot15}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{13}-\frac{1}{15}\)
\(=1-\frac{1}{15}\)
\(=\frac{14}{15}\)
Đúng 0
Bình luận (0)
1\3+1\15+1\35+1\63+1\99+1\143=1\195
1414+1515+1616+1717+1818+1919
2020+2121+2323+2424+2525
2 tim x
( 7*13+8*13):(29\3 tru x) bang 39
1\3+1\6+1\10+.....+2\x*(x+1) bang 2011\203
1/3 - 2/5 +3/35 - 4/63 + 5/99 - 6/143