tim x biet x + 3 = 8
tim x biet : /x+5/+/3-x/=8
De tim so tu nhien x ,biet rang neu lay so do tru di 3 roi chia cho 8 thi dc 12 ,ta co the viet (x-3) :8=12roi tim x , ta duoc x =99.
Bang cach lam nhu tren ,hay tim so tu nhien x,biet rang neu no nhan voi 3 roi tru di 8 ,sau do chia cho 4 thi dc 7
tim x nguyen duong biet 1/x(x+3)+1/(x+3)(x+6)=3/8
tim x biet (2.|x|+3).4-8=|-20|
( |x| . 2 + 3).4-8 = 20
( |x| . 2 + 3).4 = 20 + 8
|x| . 2 + 3 = 28 : 4
|x| . 2 = 7 - 3
|x| . 2 = 4
|x| = 4 : 2
|x| = 2
\(\Rightarrow\) x = 2 hoặc -2
Tim x, biet : 5/4 nhan x = 5/8 + 3/12
tim x biet
8+3.X=68
8 + 3.X = 68
3.X = 68 - 8
3.X = 60
X = 60 : 3
X = 20
3.X = 68 - 8
3.X = 60
X = 60 : 3
X = 20
8 + 3.x = 68
3.x = 68 - 8
3.x = 60
x = 60 : 3
x = 20
tim x,y thuoc N biet (x-6).(2y+3)=8
de tim so tu nhien x ,biet rang neu lay so dotru di 3 roi chia cho 8 thi dc12 ,ta co the viet (x-3) :8 =99
dang cach lam nhu tren ,hay tim so tu nhien x ,biet rang nhan 3 roi turu di 8 ,sau chia 4 thi dc 7
Ta có: (x.3-8):4=7
=> (x.3-8)=7.4
=> x.3-8=28
=> x.3=28+8
=> x.3=36
=> x=12
a, Cho F(x) = a x+b . Tim a,b biet f(0) = 3 va F(2) =-1
b, Cho F(x) =a x+ b. Tim a,b biet F(1) = -1 va F(-2) = 8
c, Cho F(x) =a x +b .tim a,b biet F(0) = 1 va F(-2) = -9