1. a) 17.( 15 - 16 ) + 16.( 17 - 20 )

\(=17.15-17.16+16.17-16.20\)

\(=17.15-16.20\)

\(=17.3.5-16.5.4\)

\(=5\left(17.3-16.4\right)\)

\(=5.\left(51-64\right)\)

\(=5.\left(-7\right)=-35\)

Bài 2 :

a) 10.( x - 7 ) - 8.( x + 5 ) = 6.( -5 ) + 24 

\(\Rightarrow\) 10x - 70 - 8x - 40 = -30 + 24

=> ( 10x - 8x ) = -6 + 70+40

\(\Rightarrow2x=104\)

\(\Rightarrow x=52\)

Vậy x = 52 

Tớ làm theo đúng y/c của cậu r nhé

Ko bt bài 1 có đúng ko  @@

!! Học tốt ~

#Chiyuki Fujito

1) \(=\left(\frac{3}{5}+\frac{2}{5}\right).\frac{6}{11}\)

\(=1.\frac{6}{11}\)

\(=\frac{6}{11}\)

2)\(\frac{17}{25}.\left(\frac{11}{19}+\frac{6}{19}+\frac{2}{19}\right)\)

\(=\frac{17}{25}.1\)

\(=\frac{17}{25}\)

2.\(\frac{17}{25}.\frac{11}{19}+\frac{17}{25}.\frac{6}{19}+\frac{17}{25}.\frac{2}{19}=\frac{17}{25}\left(\frac{11}{19}+\frac{6}{19}+\frac{2}{19}\right)\\ =\frac{17}{25}.1\\ =\frac{17}{25}\)

A) 137/ 12

B) 4

C) 5

b, 3/5 + 4/7 + 2/8 + 10/25 + 9/21 + 28/16

= 3/5 + 4/7 + 2/8 + 2/5 + 3/7 + 14/8

= (3/5 + 2/5) + ( 4/7 + 3/7) + ( 2/8 + 14/8)

= 1 + 1 + 7/4

= 2 + 7/4 = 15/4

c , 8/7 + 7/6 + 5/8 + 10/12 + 24/28 + 6/16 

= c , 8/7 + 7/6 + 5/8 + 5/6 + 6/7 + 1/2

= (8/7 + 6/7) + (7/6 + 5/6) + 5/8 + 1/2

= 14/7 + 12/6 + 5/8 + 1/2

= 2 + 2 + 5/8 + 1/2

= 4 + 9/8 = 41/8

\(2\left(x-5\right)-3\left(x-4\right)=-6+15.\left(-3\right)\)

\(2x-10-3x+12=-51\)

\(2-x=-51\)

\(\Rightarrow x=2-\left(-51\right)=53\)

vậy x=53

       \(2\left(x-5\right)-3\left(x-4\right)=-6+15.\left(-3\right)\)

\(\Leftrightarrow2x-10-3x+12=-51\)

\(\Leftrightarrow\left(2x-3x\right)-\left(10-12\right)=51\)

\(\Leftrightarrow-x-\left(-2\right)=-51\)

\(\Leftrightarrow-x+2=-51\)

\(\Rightarrow-x=-53\)

\(\Rightarrow x=53\)

--------Nhớ k cho mk nha bạn. Mk trả lời sớm nhất ak mà chắc cx đúng r ak nên hứa là phải k nha!!ღღღღღ---------------

Mẹ mua số kg gạo tẻ là:

      6x2=12(kg)

hack não vậy , bn viết có dấu đc không ? viết v mik ko hiểu 

tang ban 5 k voi ca diem 10 nha chuc ban hoc tot

Trả lời:

a, \(A=5\times\left(\frac{1}{5}+\frac{1}{7}\right)-\left(\frac{2}{5}+\frac{2}{17}+\frac{6}{10}+\frac{9}{51}\right)\)

\(A=5\times\left(\frac{1}{5}+\frac{1}{7}\right)-\left(\frac{2}{5}+\frac{2}{17}+\frac{3}{5}+\frac{3}{17}\right)\)

\(A=5\times\left(\frac{1}{5}+\frac{1}{7}\right)-\left(\frac{5}{5}+\frac{5}{17}\right)\)

\(A=5\times\left(\frac{1}{5}+\frac{1}{7}\right)-5\times\left(\frac{1}{5}+\frac{1}{17}\right)\)

\(A=5\times\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{5}-\frac{1}{7}\right)\)

\(A=5\times\left(\frac{1}{7}-\frac{1}{17}\right)\)

\(A=5\times\frac{10}{119}\)

\(A=\frac{50}{119}\)

  b, \(B=\frac{2003\times14+1988+2001\times2002}{2002+2002\times503+504\times2002}\)

\(B=\frac{\left(2002+1\right)\times14+1988+2001\times2002}{2002\times\left(1+503+504\right)}\)

\(B=\frac{2002\times14+14+1988+2001\times2002}{2002\times1008}\)

\(B=\frac{2002\times14+2002+2001\times2002}{2002\times1008}\)

\(B=\frac{2002\times\left(14+1+2001\right)}{2002\times1008}\)

\(B=\frac{2002\times2016}{2002\times1008}\)

\(B=2\)

c, Sửa dề 

\(\left(4,58\div3,27+5,23\div3,27\right)\times4,08-4,08\)

\(=\left[\left(4,58+5,23\right)\div3,27\right]\times4,08-4,08\)

\(=\left(9,81\div3,27\right)\times4,08-4,08\)

\(=3\times4,08-4,08\)

\(=4,08\times\left(3-1\right)\)

\(=4,08\times2\)

\(=8,16\)

d, \(\frac{6}{11}+\frac{7}{17}+\frac{8}{25}+\frac{10}{17}+\frac{16}{11}+\frac{17}{25}\)

\(=\left(\frac{6}{11}+\frac{16}{11}\right)+\left(\frac{7}{17}+\frac{10}{17}\right)+\left(\frac{8}{25}+\frac{17}{25}\right)\)

\(=2+1+1\)

\(=4\)

Lời giải:

\(\frac{4}{9}\times \frac{3}{7}\times \frac{7}{4}=\frac{1}{3}\)

\(\frac{6}{5}\times \frac{4}{5}\times \frac{25}{16}=\frac{3}{2}\)

\(\frac{7}{8}\times \frac{16}{9}\times \frac{3}{14}=\frac{1}{3}\)

a) \(625^4:25^7\)

\(=\left[25^2\right]^4:25^7\)

\(=25^8:25^7\)

\(=25\)

b)\(\left(100^5-89^5\right).\left(6^8-8^6\right).\left(8^2-4^3\right)\)

\(=\left(100^5-89^5\right).\left(6^8-8^6\right).\left[\left(2^3\right)^2-\left(2^2\right)^3\right]\)

\(=\left(100^5-89^5\right).\left(6^8-8^6\right).\left[2^6-2^6\right]\)

\(=\left(100^5-89^5\right).\left(6^8-8^6\right).0\)

\(=0\)