a)B=1+3+3²+3³+....+3⁹⁹

=(1+3)+(3²+3³)+...+(3⁹⁸+3⁹⁹)

=4+3².4+....+3⁹⁸.4

=4.(1+3²+...+3⁹⁸) chia hết cho 4

Vậy B chia hết cho 4

b)B=1+3²+3³+3⁴+...+3⁹⁹

=(1+3+3²+3³)+....+(3⁹⁶+3⁹⁷+3⁹⁸+3⁹⁹)

=40+.........+3⁹⁶.40

=40.(1+....+3⁹⁶) chia hết cho 40

Vậy B chia hết cho 40

a)B=(1+3)+(3²+3³)+...+(3⁹⁸+3⁹⁹)

=(1+3)+3²(1+3)+....+3⁹⁸(1+3)

=4+3².4+...+3⁹⁸.4

=4(1+3²+...+3⁹⁸) chia hết cho4

câu b bạn vận dụng theo câu a là đc bạn nhóm 4 lại nhé mình hơi lười làm

a)     B=3^0+3^1+3^2+  .............+3^99

=1(1+3)+3^2(1+3)+.................3^98(1+3)

=4+3^2.\(\times4+.............+3^{98}\times4\)

\(=4\left(1+3^2+............3^{98}\right)\)

\(\Rightarrow\)Bchia hết cho 4

S = 3¹⁰⁰ - 1

Ad cho xin ý kiến vs ạ

C/M C\(⋮\)4

\(C=1+3+3^2+...+3^{99}⋮4\)

\(C=\left(1+3\right)+\left(3^2+3^3\right)+...+\left(3^{98}+3^{99}\right)⋮4\)

\(C=\left(1+3\right)+3^2.\left(1+3\right)+...+3^{98}.\left(1+3\right)⋮4\)

\(C=4+3^2.4+...+3^{98}.4⋮4\)

\(C=4.\left(1+3^2+...+3^{98}\right)⋮4\)

C/M C\(⋮\)40

\(C=1+3+3^2+...+3^{99}⋮40\)

\(C=\left(1+3+3^2+3^3\right)+...+\left(3^{96}+3^{97}+3^{98}+3^{99}\right)⋮40\)

\(C=\left(1+3+3^2+3^3\right)+...+3^{96}.\left(1+3+3^2+3^3\right)⋮40\)

\(C=40.1+...+3^{96}.40⋮40\)

\(C=40.\left(1+...+3^{96}\right)⋮40\)

ai lạnh ko tui lạnh quá mà vẫn ko có ng iu

khó quá xem trên mạng

khó quá xem trên mạng

1-3+3^2-3^3+...+3^98-3^99=(1-3+3^2-3^3)+(3^4-3^5+3^6-3^7)+...+(3^96-3^97+3^98-3^99)

=-20+3^4.(1-3+3^2-3^3)+...+3^96.(1-3+3^2-3^3)

=-20+3^4.(-20)+...+3^96.(-20)

=-20.(1+3^4+...+3^96)

=-5.4.(1+3^4+...+3^96)

=>1-3+3^2-3^3+...+3^98-3^99 chia  hết cho 4

\(C=1+3^1+3^2+...+3^{99}\)

\(=\left(1+3^1\right)+\left(3^2+3^3\right)+...+\left(3^{98}+3^{99}\right)\)

\(=\left(1+3\right)+3^2\left(1+3\right)+...+3^{98}\left(1+3\right)\)

\(=4\left(1+3^2+...+3^{98}\right)\)chia hết cho \(4\).

\(C=1+3^1+3^2+...+3^{99}\)

\(=\left(1+3^1+3^2+3^3\right)+...+\left(3^{96}+3^{97}+3^{98}+3^{99}\right)\)

\(=\left(1+3^1+3^2+3^3\right)+...+3^{96}\left(1+3^1+3^2+3^3\right)\)

\(=40\left(1+3^4+...+3^{96}\right)\)chia hết cho \(40\).