có ai bt lm bài này k giúp mk vs mk đg cần rất rất gấp mong các bạn giúp cho
Có ai bt lm bài này k giúp mk vs mk đg rất rất cần mong các bạn giúp cho
đăng r hạn chế đăng lại b nhé, sẽ có ng trl mà
có ai bt lm bài này k giúp mk vs mk đg rất rất cần gấp mong các bn giúp cho
1 was arrested before the garden by the boy yesterday
2 his cats taken care of carefully by Jack everyday
3 Has the country been protected from Covid-19 successfully
4 is reported that the man is running out of money
is reported to be running out of money\
5 has been said that the thief got out of the prison
has been said to have got out of the prison
6 was thought that Mary had turned down the job
Mary was thought to have turned down the job
có ai bt giải bài này k giúp mk vs mk đg cần rất rất gấp mong các bn giúp cho( lm VD1 vs VD2 thôi nha)
Có ai bt lm bài này k giúp mk vs mk đg rất rất cần mong các bạn giúp cho (làm bài 1, bài 2 vs 3 thôi nhé)
có ai bt lm bài này k mk đg cần rất rất gấp mong các bạn giúp cho
1 hadn't seen - were
2 doesn't like - being phoned
3 is eaten
4 is leaving - will wait
5 won't be - will you go
6 is coming - don't want
7 hasn't read - have gone
8 haven't seen - left
9 was washing - was writing
10 sets - goes
11 were talking - walked
12 has stayed - studied - was
13 was made
14 had told - went away
15 will be held
16 had gone - sat - rested
17 watched - had done
Có ai bt lm bài này k giúp mk vs mk đg rất rất cần mong các bn giúp cho
Có ai bt lm bài này k giúp mk vs mk đg rất rất cần mong các bn giúp cho
Có ai bt lm bài này k giúp mk vs mk đg rất rất cần mong các bn giúp cho
Có ai bt lm bài này k giúp mk vs mk đg rất rất cần mong các bn giúp cho
Bài 3:
\(a,=\sqrt[3]{\left(x-1\right)^3}-\sqrt[3]{\left(5x+1\right)^3}=x-1-5x-1=-4x-2\\ b,=6a-6a+20a=20a\)
Bài 2:
\(a,=2\sqrt[3]{6}+3\sqrt[3]{5}-4\sqrt[3]{6}-2\sqrt[3]{5}=\sqrt[3]{5}-2\sqrt[3]{6}\\ b,=\sqrt[3]{8}-4\sqrt[3]{27}+2\sqrt[3]{64}=2-12+16=6\\ c,=\sqrt[3]{64}+\sqrt[3]{48}+\sqrt[3]{36}-\sqrt[3]{48}-\sqrt[3]{36}-\sqrt[3]{27}=4-3=1\\ d,=\sqrt[3]{162\left(-2\right)\cdot\dfrac{2}{3}}=\sqrt[3]{-216}=-6\)