\(.5^{x-3}-2.5^2=3.5^2\)

\(5^{x-3}=25\)

Ta có :

\(5^2=25\)

=> x-3 = 2

=> x=5

5^x-3-2.5²=3.5²

5^x-3=3.5²+2.5²

5^x-3=5².(3+2)

5^x-3=5².5

5^x-3=5³

=>x-3=3

x=6

5^x-3-2.5²=3.5²

5^x-3=3.5²+2.5²

5^x-3=5².(3+2)

5^x-3=5².5

5^x-3=5³

=>x-3=3

x=6

ban hoc o truong nao ak

\(x\left(2-y\right)-y+2-2=5\)

\(\left(2-y\right)\left(x+1\right)=7\)

⇒ (x+1) và (2-y) ϵ {-1;1;-7;7}

⇒ (x;y) ϵ {(-2;5);(0;-5);(-8;3);(6;1)}

Mai always gets up early and does morning excercise in the morning

He bought some books to read at home

She sometimes helps her Mother cook dinner

Mai was happy at the party

1.Mai always gets up early and does exercise in the morning.

2, He bought some books to read at home.

3.She sometimes help her mother cook dinner

4.Mai was happy at the party.

\(\left(5-2x\right)^2-16=0\)

\(\Leftrightarrow\left(5-2x\right)^2-4^2=0\)

\(\Rightarrow\left(5-2x-4\right)\left(5-2x+4\right)=0\)

\(\Rightarrow\orbr{\begin{cases}5-2x-4=0\\5-2x+4=0\end{cases}\Leftrightarrow\orbr{\begin{cases}-2x=4-5\\-2x=-4-5\end{cases}}\Leftrightarrow\orbr{\begin{cases}-2x=-1\\-2x=-9\end{cases}}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{-1}{-2}=\frac{1}{2}\\x=\frac{-9}{-2}=\frac{9}{2}\end{cases}}\)

Vậy ................................

= 5^2 - 2.5.2x + (2x)\(^2\)- 16 = 0

=> x = 4,5

Cam on ban nhieu nha <3

\(3\left(x-1\right)^2-3x\left(x-5\right)=1\)

\(\Leftrightarrow\)\(3x^2-6x+3-3x^2+15x=1\)

\(\Leftrightarrow\)\(9x=-2\)

\(\Leftrightarrow\)\(x=-\frac{2}{9}\)

Vậy...

\(x^2-2x+1=25\)

\(\Leftrightarrow\)\(x^2-2x-24=0\)

\(\Leftrightarrow\)\(\left(x+4\right)\left(x-6\right)=0\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x+4=0\\x-6=0\end{cases}}\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x=-4\\x=6\end{cases}}\)

Vậy...