tim x biet (x-2015)2015=1
Tim x la so tu nhien, biet:
x - 4/2015 - 1/2015 = 10 - 2x
tim x biet x^2015=1^x
tim x biet (x-1)^2017=4*(x-1)^2015
(x - 1)2017 = 4(x - 1)2015
=> (x - 1)2017 - 4(x - 1)2015 = 0
=> (x - 1)2015.(x - 1)2 - 4(x - 1)2015 = 0
=> (x - 1)2015.[(x - 1)2 - 4] = 0
=> (x - 1)2015 = 0 hoặc (x - 1)2 - 4 = 0
=> x - 1 = 0 hoặc (x - 1)2 = 4
=> x = 1 hoặc x - 1 = 2 hoặc x - 1 = -2
=> x = 1 hoặc x = 3 hoặc x = -1
Vậy x = {-1;1;3}
(x-1)^2017=4*(x-1)^2015
(x-1)^2017/(x-1)^2015=4
(x-1)^2=4
(x-1)=2 hoặc -2
giải tiếp....................
(x - 1)2017 = 4.(x - 1)2015
=> (x - 1)2017 - 4(x - 1)2015 = 0
=> (x - 1)2015.(x - 1)2 - 4(x - 1)2015 = 0
=> (x - 1)2015.[(x - 1)2 - 4] = 0
=> \(\orbr{\begin{cases}\left(x-1\right)^{2015}=0\\\left(x-1\right)^2-4=0\end{cases}}\)=>\(\orbr{\begin{cases}x-1=0\\\left(x-1\right)^2=4=2^2\end{cases}}\)
=> \(\orbr{\begin{cases}x=1\\x-1=2\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=3\end{cases}}}\)
Vậy x = {1;3}
1. Tim x biet : \(2015-\left|x-2015\right|=x;\left|x\right|=-x-5\)
2015-|x-2015|=x
=>|x-2015|=2015-x
=>|x-2015=-(x-2015)
=>x-2015 < 0
=>x < 2015
ko chắc nữa
tim x biet /x-2015/=1
Nhớ nhấn đúng cho mình nhé Lê Nguyễn Thúy Vi
/ x - 2015 / =1
\(\Rightarrow\int^{x-2015=-1}_{x-2015=1}\)
\(\Rightarrow\int^{x=-1+2015=2014}_{x=1+2015=2016}\)
tim x nguyen biet /x-1/^2+(x-1)^2=2015./x-1/
tim x
giup dum
Tim STN x, y biet:
a,25y+15x=126
b, 2016x-1=y-2015-|y-2015|
tim x biet
b, (x-1)^2010=(x-1)^2015
a,TH1:x+2=0
x =0-2
x =-2
TH2:x^2-64=0
x^2 =0+64
x^2 =64
Mà : x^2 =8^2
Vay x=8
cau b ko bt
tim x biet (2x+1)+(2x+2)+...+(2x+2015)