\(\dfrac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)  (sửa \(-9^9\rightarrow.9^9\))

\(=\dfrac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)

\(=\dfrac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)

\(=\dfrac{2^{29}.3^{18}\left(15-9\right)}{2^{28}.3^{18}\left(15-14\right)}\)

\(=2.6=12\)

\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.3^{19}.2^{19}-7.2^{29}.\left(3^3\right)^6}=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}=\frac{3^{18}.\left(5.2^{30}-2^{29}.3^2\right)}{3^{18}.\left(5.2^{28}.3-7.2^{29}\right)}=\frac{2^{28}.\left(5.2\right)}{2^{28}\left(5.3-7.2\right)}=\frac{10}{15-14}=\frac{10}{1}=10\)

Có j sai mong bỏ qua

Học tốt

Xét tử :

5.4¹⁵.9⁹ - 4.3²⁰.8⁹

= 5.2³⁰.3¹⁸ - 2² . 3²⁰ . 2²⁷

= 5 . 2³⁰ . 3¹⁸ - 2²⁹ . 3²⁰

= 3¹⁸ . 2²⁰ . ( 5 . 2¹⁰ - 2⁹ . 3² )

= 3¹⁸ . 2²⁰ . [ 2⁹ . ( 5 . 2 - 3² ) ]

= 3¹⁸ . 2²⁰ . 2⁹

= 3¹⁸ . 2²⁹

Xét mẫu :

5.2⁹.6¹⁹ - 7.2²⁹.27⁶

= 5 . 2⁹ . 2¹⁹ . 3¹⁹ - 7 . 2²⁹ . 3¹⁸

= 5 . 2²⁸ . 3¹⁹ - 7 . 2²⁹ . 3¹⁸

= 3¹⁸ . 2²⁸ . ( 5 . 3 - 7 . 2 )

= 3¹⁸ . 2²⁸

B = \(\frac{3^{18}.2^{29}}{3^{18}.2^{28}}=2\)

\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)\(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\frac{2.1}{1}=2\)

học tốt ~~~

\(\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^9\cdot6^{19}-7\cdot2^{29}\cdot27^6}\\ =2\)

B= {[ 5 * (2^2)^15 * (3^2)^9 ] - [ (2^2) * 3^20 * (2^3)^9 ]} / {[ 5 * (2^9) * (2^19)*(3^19) ] - [ 7 * (2^29) * (3^3)^6 ]} 
B= {[ 5 * (2^30) * (3^18) ] - [ (3^20) * (2^29) ]} / {[ 5 * (2^28) * (3^19) ] - [ 7 * (2^29) * (3^18) ]} 
B= {[ (2^29) * (3^18) ] * [(5 * 2) - 3^2 ]} / {[ (2^28) * (3^18) ] - [(5 * 3) - (7 * 2)] } 
B= [ (2^29) * (3^18) ] / [ (2^28) * (3^18) ] 
B= [ (2^1) * (2^28) * (3^18) ] / [ (2^28) * (3^18) ] 
B = 2

ta có \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)=\(\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)=\(\frac{2^{29}.3^{18}\left(2.5-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}\)=2

Đặt \(A=\frac{5.4^{15}.9^9+4.3^{20}.8^9}{5.2^9.6^{19}+7.2^{29}.27^6}\)

\(A=\frac{5.2^{30}.3^{18}+2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}+7.2^{29}.3^{18}}\)\(A=\frac{2^{28}\left(5.2^2.3^{18}+2.3^{20}\right)}{2^{28}\left(5.3^{19}+7.2.3^{18}\right)}\)

\(A=\frac{5.2^2.3^{18}+2.3^{20}}{5.3^{19}+7.2.3^{18}}\)\(A=\frac{3^{18}\left(5.2^2+2.3^2\right)}{3^{18}\left(5.3+7.2\right)}\)\(=\frac{5.2^2+2.3^2}{5.3+7.2}\)

\(=\frac{38}{29}=1\frac{9}{29}\)

Ta có : \(\frac{5.4^{15}.9^9+4.3^{20}.\left(-8\right)^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)

\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\frac{2^{29}.3^{18}}{2^{28}.3^{18}}=2\)