\(4x^2-y^2-6x+3y\)

\(=\left(2x\right)^2-y^2-3\left(2x-y\right)\)

\(=\left(2x-y\right)\left(2x+y\right)-3\left(2x-y\right)\)

\(=\left(2x-y\right)\left(2x+y-3\right)\)

Phân tích đa thức thành nhân tử :

\(4x^2-y^2-6x+3y\)

\(=\left(2x-y\right)\left(2x+y\right)-3\left(2x-y\right)\)

\(=\left(2x-y\right)\left(2x+y+3\right)\)

mk xl nhé, mk ghi sai dấu 

Sửa lại phần cuối :

\(\left(2x-y\right)\left(2x+y-3\right)\)

\(6x^3y^2-4x^3y^3=2x^3y^2\left(3x-2\right)\)

1. 5x² - 4x

= x(5x - 4)

2. 8x²(x - 3y) - 12x(x - 3y)

= (8x² - 12x)(x - 3y)

= 4x(2x - 3)(x - 3y)

3. 3(x - y) - 5x(y - x)

= 3(x - y) + 5x(x - y)

= (3 + 5x)(x - y)

a) \(=3\left(5y+4x\right)\)

b) \(=\left(x-3\right)^2\)

c) \(=y\left(y^2+2y+3\right)\)

a) x³-2x²-x+2

=x(x²-1)+2(-x²+1)

=x(x²-1)-2(x²-1)

=(x²-1)(x-2)

b)

x²+6x-y²+9

=x²+6x+9-y²

=(x+3)²-y²

^{=(x+3-y)(x+3+y)}

a)

3x³y²+6x²y⁴=3x²y²*(x+y²)

b)

16-4x²=4*(4-x²)

c)

xy+xz+5x+5y=(xy+5y)+(xz+5x)

                   =y*(x+5)+x*(z+5)

                  =(x+5+z+5)*(y+x)

                  =5*(x+z)*(x+y)

Ta có :  4 x 2 - 6 x = 2 x . 2 x - 3 . 2 x = 2 x ( 2 x - 3 ) .

\(x^2-y^2+4-4x\)

\(=\left(x-2\right)^2-y^2\)

\(=\left(x-y-2\right)\left(x-2+y\right)\)

giải thích chi tiết giúp e ạ.e cảm ơn

\(3x^2-3y^2-12x-12y\)

\(=3\left(x+y\right)\left(x-y\right)-12\left(x+y\right)\)

\(=\left(x+y\right)\left(3x-3y-12\right)\)