\(A=\left|3,7-x\right|+2,5\ge2,5\)

\(MinA=2,5\Leftrightarrow3,7-x=0\Rightarrow x=3,7\)

\(B=\left|x+1,5\right|+4,5\ge4,5\)

\(MinB=4,5\Leftrightarrow x+1,5=0\Rightarrow x=-1,5\)

Tìm GTLN nhỉ?

a) Ta có: \(A=1,5-\left|x+1,1\right|\le1,5\left(\forall x\right)\)

Dấu "=" xảy ra khi: \(\left|x+1,1\right|=0\Rightarrow x=-1,1\)

Vậy Max(A) = 1,5 khi x = -1,1

b) Ta có: \(B=-3,7-\left|-1,7-x\right|\le-3,7\left(\forall x\right)\)

Dấu "=" xảy ra khi: \(\left|-1,7-x\right|=0\Rightarrow x=-1,7\)

Vậy Max(B) = -3,7 khi x = -1,7

324,84375 nha

1.5 x 2.5 x 3.5 x 4.5 x 5.5 = 324.84375

Mik ko hỉu đè bạn ơi dấu . là j z!

Ta có:

\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)

\(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.11}{5.7}=\frac{22}{35}\)

\(A=-4,5+\left|x-1,5\right|\ge-4,5\)

\(Min_A=-4,5\)

\(\Leftrightarrow x=1,5\)

b) \(\left(x-3\right)^2=0,25\)

\(\Rightarrow\left(x-3\right)^2=\left(\pm0,5\right)^2\)

\(\Rightarrow x-3=\pm0,5.\)

\(\Rightarrow\left[{}\begin{matrix}x-3=0,5\\x-3=-0,5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0,5+3\\x=\left(-0,5\right)+3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3,5\\x=2,5\end{matrix}\right.\)

Vậy \(x\in\left\{3,5;2,5\right\}.\)

c) \(\left(2x-1,5\right)^3=\left(-0,27\right)\) (câu này sai đề rồi nhé).

d) \(3.2x+\left(-1,2\right).x+2,7=\left(-4,9\right)\)

\(\Rightarrow3.2x+\left(-1,2\right).x=\left(-4,9\right)-2,7\)

\(\Rightarrow3.2x+\left(-1,2\right).x=-7,6\)

\(\Rightarrow6.x+\left(-1,2\right).x=-7,6\)

\(\Rightarrow\left[6+\left(-1,2\right)\right].x=-7,6\)

\(\Rightarrow4,8.x=-7,6\)

\(\Rightarrow x=\left(-7,6\right):4,8\)

\(\Rightarrow x=-\frac{19}{12}\)

Vậy \(x=-\frac{19}{12}.\)

Chúc bạn học tốt!

b) (x-3)\(^2\) = 0,25

(x-3)\(^2\) = (0,5)\(^2\)

x-3 = 0,5

x = 0,5 + 3

x = 0,8