tính :S= 1/3 + 1/9 + 1/27 + 1/135 + 1/405
Tính nhanh A= 1/5+ 1/15 + 1/45+ 1/135 + 1/405
ta có : 1/5+1/15=1-1/15=14/15
vậy 1/5+1/15+1/45+1/135+1/405=1-1/405=404/405
404/405 NHỚ **** ĐÓ
\(\frac{121}{405}\)
ta có :1/5 + 1/15 = 1- 1/15 =14/15
vậy :1/5 + 1/15 + 1/45 + 1/135 + 1/405 = 1- 1/405 = 404/405
đáp số : 404/405
Tính S2 = 1 + 3 - 5 - 7 + 9 + 11 - ....- 405
Bài 1;tính
A=1/2*9+1/9*7+1/7*19+....+1/252*509
B=1/10*9+1/18*13+/26*17+....+1/802*405
C=2/4*7-3/5*9+2/7*10-3/9*13+...+2/301*304-3/401*405
Bài 2
Cho S=1/5^2+1/9^2+...+1/409^2
Chứng minh S<1/12
4S = 4/(5x5) + 4/(9x9) + … + 1/(409x409)
Ta thấy:
4/(5x5) < 4/(3x7) = 1/3 – 1/7
4/(9x9) < 4/(7x11) = 1/7 – 1/11
…………
4/(409x409) < 4/(407x411) = 1/407 – 1/411
Mà :
4/(3x7) + 4/(7x11) + …. + 4/(407x411) = 1/3 – 1/411 = 136/411
4S < 136/411
S < 34/411 < 34/408 = 1/12
Hay S < 1/12
Tính
A=1/2×9+1/9×7+1/7×19+...+1/252×509
B=1/10×9+1/18×13+1/26×17+...+1/802×405
C=2/4×7-3/5×9+2/7×10-3/9×13+...+2/301×304-3/401×405
B = \(\frac{1}{10.9}+\frac{1}{18.13}+\frac{1}{26.17}+...+\frac{1}{802.405}\)
B = \(\frac{2}{10.18}+\frac{2}{18.26}+\frac{2}{26.34}+...+\frac{2}{802.810}\)
B = \(\frac{1}{4}.\left(\frac{1}{10}-\frac{1}{18}+\frac{1}{18}-\frac{1}{26}+\frac{1}{26}-\frac{1}{34}+...+\frac{1}{802}-\frac{1}{810}\right)\)
B = \(\frac{1}{4}.\left(\frac{1}{10}-\frac{1}{810}\right)=\frac{1}{4}.\frac{8}{81}\)
B = \(\frac{2}{81}\)
tìm x, biết:
a. 2 . 3x - 405 = 3^x - 1
b.(1/81)^x . 27^2x = (-9)^4
1 S=1-3+5-7+....+2001-2003
2 S=1+3-5-7+9+11-.....-405-407
3 S=2-5+8-11+...110-113
a) 1−3+5−7+...+2001−2003+2005=(−2)+(−2)+...+(−2)+2005 (501 số −2) =501.(−2)+2005=1003
S=1+3-5-7+9+11-....-405-407
S = \(81\) + \(27\) + \(9\) + \(3\) ... + \(\dfrac{1}{27}\) + \(\dfrac{1}{81}\)
Tính S giúp mik với ạ, ai nhanh mik tick
\(3S=241+81+27+9+...+\dfrac{1}{9}+\dfrac{1}{27}\)
\(2S=3S-S=241-\dfrac{1}{81}=\dfrac{241x81-1}{81}\)
\(\Rightarrow S=\dfrac{241x81-1}{2x81}\)
Tinh Nhanh:
A= 1/5+1/15+1/45+1/135+1/405
Vậy A=?