10.\(\frac{4^6.9^5+6.^9120}{8^4.3^{12}-6^{11}}\)
Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
Tính giá trị của biểu thức(tính nhanh nếu có thể):
1)\(\frac{35.\left(27^{8^{ }}+2.9^{11}\right)}{^{ }15.\left(81^6-12.3^{19}\right)}\)
2)\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
3)\(\frac{4^6.9^5+6.^9120}{-8^4.3^{12}-6^{11}}\)
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\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}.10\)
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}.10=\frac{2^{12}.3^{10}+2^9.3^9.120}{2^{12}.3^{12}-2^{11}.3^{11}}.10=\frac{2^{10}.3^{10}\left(2^2+20\right)}{2^{10}.3^{10}\left(6^2-6\right)}.10=\frac{24.10}{30}=8\)
\(10.\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
10.46.95+69.120 :; 84.312-611
$\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}$
Rút gọn biểu thức: \(10.\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
tính biểu thức \(10.\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
=5^1+3+5+7+.....+49
Số các số hạng từ 1 đến 49 là (49-1):1+1=50
Tổng các số từ 1 đên 49 là (49+1).50:2=1250
=5^1250
Tính hợp lí :
a ) 10 . \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}.6^{11}}\)
Sửa đề : \(10.\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(10\cdot\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)
\(=10\cdot\frac{2^{12}\cdot3^{10}+2\cdot9\cdot3^9\cdot2^3\cdot3\cdot5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=10\cdot\frac{2^{12}\cdot3^{10}\cdot\left(1+5\right)}{2^{11}\cdot3^{11}\cdot\left(2\cdot3-1\right)}\)
\(=10\cdot\frac{2\cdot6}{3\cdot5}=8\)
Bài làm:
\(10.\frac{4^6.9^5+6^9.120}{8^4.3^{12}.6^{11}}\)
\(=\frac{2.5.2^{12}.3^{10}+2^9.3^9.2.5.2^2.3}{2^{12}.3^{12}.2^{11}.3^{11}}\)
\(=\frac{2^{13}.3^{10}.5+2^{12}.3^{10}.5}{2^{23}.3^{23}}\)
\(=\frac{2^{12}.3^{10}.5\left(2+1\right)}{2^{23}.3^{23}}\)
\(=\frac{2^{12}.3^{11}.5}{2^{23}.3^{23}}=\frac{5}{2^{11}.3^{12}}\)
sợ sai
Tính hợp lí:
\(10\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
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4/5
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{2^{12}.3^{10}+3^{10}.2^{12}.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}.6}{6^{12}-6^{11}}=\frac{2^{12}.3^{10}.6}{6^{11}\left(6-1\right)}=\frac{2^{10}.3^{10}\left(2^2+1\right).6}{6^{11}.5}=\frac{6^{11}.5}{6^{11}.5}=1\)