\(\frac{3\cdot x-0.8}{x}+14.5=15\)
a.\(x+x\cdot\frac{1}{3}:\frac{2}{9}+x:\frac{2}{7}=252\)
b.\(\left(3\cdot x-0.8\right):x+14.5=15\)
a ) \(x+x\times\frac{1}{3}\div\frac{2}{9}+x\div\frac{2}{7}=252\)
\(x\times1+x\times\frac{1}{3}\div\frac{2}{9}+x\div\frac{2}{7}=252\)
\(x\times1+x\times\frac{1}{3}\times\frac{9}{2}+x\times\frac{7}{2}=252\)
\(x\times1+x\times\frac{9}{6}+x\times\frac{7}{2}=252\)
\(x\times\left(1+\frac{9}{6}+\frac{7}{2}\right)=252\)
\(x\times6=252\)
\(x=252\div6\)
\(x=42\)
b ) \(\left(3\times x-0,8\right)\div x+14,5=15\)
\(\left(3\times x-0,8\right)\div x=15-14,5\)
\(\left(3\times x-0,8\right)\div x=0,5\)
\(0,8\div x=3-0,5\)
\(0,8\div x=2,5\)
\(x=0,8\div2,5\)
\(x=0,32\)
3 x X - 0.8 / X -14.5 = 15
(X x 3 - 0,8) : X + 14,5 = 15
3 x X - 0.8 / X -14.5 = 15
Tìm x
( 3 x - 0.8 ) : x + 14.5 = 15
( 3 x - 0.8 ) : x + 14.5 = 15
( 3 x - 0.8 ) x \(\frac{1}{x}\)+ 14,5 = 15
3X x \(\frac{1}{x}\)- 0,8 x \(\frac{1}{x}\)= 0,5
\(\frac{3x}{x}-\frac{0,8}{x}=\frac{0,5x}{x}\)
=> 3x - 0,8 = 0,5x
3x - 0,5x = 0,8
2,5x = 0,8
x = 2,5 : 0,8
x = \(\frac{25}{8}=3,125\)
(3×y-0.8):y+14.5=15
Giup mik bai nay nhaaa
so sánh A và B biết:
A=\(\left[0.8\cdot7+\left(0.8\right)^2\right]\cdot\left(1.25\cdot7-\frac{4}{5}\cdot1.25\right)-47.86\)
B=\(\frac{\left(1.09-0.29\right)\cdot\frac{5}{4}}{\left(18.9-16.65\right)\cdot\frac{8}{9}}\)
\(A=\left[0,8\cdot7+(0,8)^2\right]\cdot\left[1,25\cdot7-\frac{4}{5}\cdot1,25\right]-47,86\)
\(=0,8\cdot(7+0,8)\cdot1,25\cdot(7-0,8)-47,86\)
\(=0,8\cdot7,8\cdot1,25\cdot6,2-47,86\)
\(=48,36-47,86=0,5\)
\(B=\frac{(1,09-0,29)\cdot\frac{5}{4}}{(18,9-16,65)\cdot\frac{8}{9}}=\frac{0,8\cdot1,25}{2,25\cdot\frac{8}{9}}=\frac{1}{2}\)
\(A:B=0,5:\frac{1}{2}=\frac{1}{2}:\frac{1}{2}=\frac{1}{2}\cdot2=1\)
A gấp 1 lần B
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Tìm x thỏa mãn: \(\frac{5}{9}-1\frac{1}{9}\cdot x=\frac{2}{3}-\frac{15}{9}\cdot x\)
\(\frac{2\cdot x^4-5\cdot x^3+2\cdot x^2-5\cdot x-30}{x^2+10\cdot x-15}\) với x=\(-\sqrt{5}\)
Tìm x:
\(\frac{\left(13\frac{2}{9}-15\frac{2}{3}\right)\cdot\left(30^2-5^4\right)}{\left(18\frac{3}{7}-17\frac{1}{4}\right)\cdot\left(25-12\cdot5^2\right)}\cdot x=\frac{\frac{2}{11}+\frac{3}{13}+\frac{4}{15}+\frac{5}{17}}{4\frac{1}{11}+\frac{5}{13}+\frac{9}{15}+\frac{13}{17}}\)