\(\Rightarrow\frac{3}{4}x+5-\frac{2}{3}x+4-\frac{1}{6}x-1=\frac{1}{3}x+4-\frac{1}{3}+3\)+3

\(\Rightarrow\left(\frac{3}{4}x-\frac{2}{3}x-\frac{1}{6}x\right)+\left(5+4-1\right)=\frac{1}{3}x+\left(4-\frac{1}{3}+3\right)\)

=>\(\frac{-1}{12}x+8=\frac{1}{3}x+\frac{20}{3}\)\(\Rightarrow\frac{-1}{12}x+8-\frac{1}{3}x=\frac{20}{3}\)

\(\Rightarrow\left(\frac{-1}{12}-\frac{1}{3}\right)x+8=\frac{20}{3}\)

\(\Rightarrow\frac{-5}{12}x+8=\frac{20}{3}\Rightarrow\frac{-5}{12}x=\frac{20}{3}-8\)

\(\Rightarrow\frac{-5}{12}x=\frac{-4}{3}\Rightarrow x=\frac{-4}{3}:\frac{-5}{12}=\frac{16}{5}\)

\(\left(3-\frac{1}{2}x\right)\left(\left|x+\frac{3}{4}\right|-\frac{5}{6}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}3-\frac{1}{2}x=0\\\left|x+\frac{3}{4}\right|-\frac{5}{6}=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}\frac{1}{2}x=3\\\left|x+\frac{3}{4}\right|=\frac{5}{6}\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}x=6\\x=\frac{1}{12}\\x=\frac{-19}{12}\end{cases}}\)

\(\left(3-\frac{1}{2}x\right)\cdot\left(\left|x+\frac{3}{4}\right|-\frac{5}{6}\right)=0\)

\(\Rightarrow\hept{\begin{cases}3-\frac{1}{2}x=0\\\left|x+\frac{3}{4}\right|-\frac{5}{6}=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=6\\x+\frac{3}{4}=\pm\frac{5}{6}\end{cases}}\)

Ta có

\(x+\frac{3}{4}=\pm\frac{5}{6}\)

\(\hept{\begin{cases}x+\frac{3}{4}=\frac{5}{6}\\x+\frac{3}{4}=-\frac{5}{6}\end{cases}\Rightarrow\hept{\begin{cases}x=\frac{1}{12}\\x=-\frac{19}{12}\end{cases}}}\)

Vậy \(x\in\left\{3;\frac{1}{2};-\frac{19}{12}\right\}\)

\(\left(3-\frac{1}{2}.x\right).\left(|x+\frac{3}{4}|-\frac{5}{6}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}3-\frac{1}{2}.x=0\\|x+\frac{3}{4}|-\frac{5}{6}=0\end{cases}\Rightarrow\orbr{\begin{cases}\frac{1}{2}.x=3\\|x+\frac{3}{4}|=\frac{5}{6}\end{cases}\Rightarrow}\orbr{\begin{cases}x=6\\x+\frac{3}{4}=\frac{5}{6}\end{cases}\Rightarrow}\orbr{\begin{cases}x=6\\x=\frac{1}{12}\end{cases}}}\)

( 1/7 . x - 2/7 ) . ( -1.5 . x + 3/5 ) . ( 1/ 3 . x + 4/3) + 0

 <=> +) 1/7 . x - 2/7 = 0                                    +)    (- 1 / 5) . x +3/5 = 0                              +)  1/ 3 . x + 4/ 3 = 0

                    x = 2                                                                  x = 3                                                         x = 4

                                                    Vậy x = 2 : x = 3 ; x=4

a) 

( 4x - 9 ) ( 2,5 + (-7/3) . x ) = 0

\(\Rightarrow\orbr{\begin{cases}4x-9=0\\2,5+\frac{-7}{3}x=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{9}{4}\\x=\frac{15}{14}\end{cases}}\)

P/s: đợi xíu làm câu b

b) \(\frac{1}{x\left(x+1\right)}\cdot\frac{1}{\left(x+1\right)\left(x+2\right)}\cdot\frac{1}{\left(x+2\right)\left(x+3\right)}-\frac{1}{x}=\frac{1}{2015}\)

\(\frac{1}{x}-\frac{1}{x+1}+\frac{1}{x+1}-\frac{1}{x+2}+\frac{1}{x+2}-\frac{1}{x+3}-\frac{1}{x}=\frac{1}{2015}\)

\(\frac{-1}{x+3}=\frac{1}{2015}\)

\(\Leftrightarrow x+3=-2015\)

\(\Leftrightarrow x=-2018\)

Vậy,.........

A/ Ta có số nào nhân với 0 cx = 0 

Vậy từ đó suy ra 2 trường hợp 

TH1\(4x-9=0\)

\(=>x=\frac{9}{4}\)

TH2 \(2,5+-\frac{7}{3}x=0\)

 \(=>x=\frac{15}{14}\)

lam sao bạn viết chữ to như 3/4 . ( x + 1/2 ) vậy

Bài làm:

Ta có: \(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.....\frac{30}{62}.\frac{31}{64}=2^x\)

\(\Leftrightarrow\frac{1.2.3.....30.31}{2.2.2.3.2.4.....2.31.2.32}=2^x\)

\(\Leftrightarrow\frac{1}{2^{31}.2^5}=2^x\)

\(\Leftrightarrow\frac{1}{2^{36}}=2^x\)

\(\Rightarrow x=-36\)

mk cần cả giải thích

giúp mk vs!!!

Vi \(\left(\frac{1}{7}x-\frac{2}{7}\right)\cdot\left(-\frac{1}{5}x+\frac{3}{5}\right)\cdot\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)

\(\Rightarrow\hept{\begin{cases}\frac{1}{7}x-\frac{2}{7}=0\\-\frac{1}{5}x+\frac{3}{5}=0\\\frac{1}{3}x+\frac{4}{3}=0\end{cases}\Rightarrow\hept{\begin{cases}\frac{1}{7}x=\frac{2}{7}\\-\frac{1}{5}x=-\frac{3}{5}\\\frac{1}{3}x=-\frac{4}{3}\end{cases}\Rightarrow}\hept{\begin{cases}x=2\\x=3\\x=-4\end{cases}}}\)

Vậy \(x\in\left\{-4;3;2\right\}\)

\(\Rightarrow\frac{1}{7}x-\frac{2}{7}=0\text{ hoặc }-\frac{1}{5}x+\frac{3}{5}=0\text{ hoặc }\frac{1}{3}x+\frac{4}{3}=0\)

\(\Rightarrow x=2\text{ hoặc }x=3\text{ hoặc }x=-4\)

Vậy tập nghiệm của pt là \(S=\left\{2;3;-4\right\}\) 

Mấy câu trên dễ rồi mình hướng dẫn bạn làm câu d và e

d)

\(\left(x-\frac{2}{3}\right)\cdot\left(1-\frac{4}{16}x\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-\frac{2}{3}=0\\1-\frac{1}{4}x=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{2}{3}\\x=4\end{cases}}\)

Câu e, tương tự nhé bạn

a. \(\frac{3}{4}x-\frac{1}{5}=\frac{2}{3}\)

\(\frac{3}{4}x=\frac{13}{15}\)

\(x=\frac{52}{45}\)

b. \(\frac{2}{5}.\left(x+1\right)-\frac{1}{2}=0\)

\(\frac{2}{5}.\left(x+1\right)=\frac{1}{2}\)

\(x+1=\frac{5}{4}\)

\(x=\frac{1}{4}\)

c.\(\frac{1}{5}.x-\frac{2}{3}=\frac{4}{8}\)

\(\frac{1}{5}.x=\frac{7}{6}\)

\(x=\frac{35}{6}\)

d. \(\left(x-\frac{2}{3}\right).\left(1-\frac{4}{16}x\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-\frac{2}{3}=0\\1-\frac{4}{16}x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0+\frac{2}{3}\\\frac{4}{16}x=1\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{2}{3}\\x=4\end{cases}}}\)

Vậy x = 2/3 hoặc x = 4

e. \(\left(0,32-x\right).\left(4,5-\frac{3}{2}x\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}0,32-x=0\\4,5-\frac{3}{2}x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0,32-0\\\frac{3}{2}x=4,5\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=0,32\\x=3\end{cases}}}\)

Vậy x = 0,32 hoặc x = 3