Tìm x
a.\(-5|x-\frac{1}{4}|=\frac{5}{3}:|\frac{-10}{9}|\)
CAc bn giúp mik với mai mik nộp rồi
Tìm x
a.\(|-2x+\frac{1}{3}|=|x-\frac{1}{6}|\)
Các bn giúp mik với mai mik nộp rồi
1.Tìm x
a.\(-\frac{2}{3}.|-\frac{1}{2}x-\frac{1}{3}|=0\)
Các bn ơi giúp mik với mai mik nộp rồi
\(-\frac{2}{3}.\left|-\frac{1}{2}x-\frac{1}{3}\right|=0\)
\(\Rightarrow\left|-\frac{1}{2}x-\frac{1}{3}\right|=0\)
\(\Rightarrow-\frac{1}{2}x-\frac{1}{3}=0\)
\(\Rightarrow-\frac{1}{2}x=\frac{1}{3}\)
\(\Rightarrow x=-\frac{2}{3}\)
\(\Leftrightarrow\left|-\frac{1}{2}x-\frac{1}{3}\right|=0\)
\(\Leftrightarrow\)\(\frac{-1}{2}x-\frac{1}{3}\)\(=0\)
\(\Leftrightarrow-\frac{1}{2}x=\frac{1}{3}\)
\(\Leftrightarrow x=\frac{-2}{3}\)
vậy....
1. Tìm x thuộc Z biết:
a,\(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\)
b,\(\left(\frac{-5}{3}\right)^3< x< \frac{-24}{35}.\frac{-5}{6}\)
2. Thực hiện phép tính:
a,\(\left(\frac{9}{10}-\frac{15}{16}\right).\left(\frac{5}{12}-\frac{11}{15}-\frac{7}{20}\right)\)
b,\(\frac{-3}{5}+\frac{28}{5}.\left(\frac{43}{56}+\frac{5}{24}-\frac{21}{63}\right)\)
AI GIÚP MIK VỚI,MIK DÂNG CẦN GẤP,SÁNG MAI MIK PHẢI NỘP CHO CÔ RỒI,GIÚP MIK NHA
1)
a)
\(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\)
\(\frac{-1}{1}.\frac{20}{5}< x< \frac{-1}{5}.\frac{3}{2}\)
\(\frac{-20}{5}< x< \frac{-3}{10}\)
\(\frac{-40}{10}< x< \frac{-3}{10}\)
\(\Rightarrow Z\in\left\{-4;-5;-6;-7;-8;-9;-10;...;-39\right\}\)
\(\left(\frac{-5}{3}\right)^3< x< \frac{-24}{35}.\frac{-5}{6}\)
\(\frac{25}{3}< x< \frac{-4}{7}.\frac{1}{1}\)
\(\frac{-25}{3}< x< \frac{-4}{7}\)
\(\frac{-175}{21}< x< \frac{-12}{21}\)
\(\Rightarrow Z\in\left\{-13;-14;-15;-16;...;-174\right\}\)
2)
a)
\(\left(\frac{9}{10}-\frac{15}{16}\right).\left(\frac{5}{12}-\frac{11}{15}-\frac{7}{20}\right)\)
\(=\left(\frac{72}{80}-\frac{75}{80}\right).\left(\frac{25}{60}-\frac{44}{60}-\frac{21}{60}\right)\)
\(=\frac{-3}{80}.\frac{-40}{60}\)
\(=\frac{-1}{-2}.\frac{-1}{-20}\)
\(=\frac{1}{40}\)
1.
tìm x
\(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}\right)x=\)\(\frac{1}{5}\)
2. Tìm a, b\(\in\)N:
BCNN(a, b)=180
ƯCLN (a, b) = 12
Mong các bn giúp đỡ!
sáng mai mik phải nộp rồi......
bài1.Thực hiện phép tính(tính hợp lí nếu có thể)
a,\(4\frac{1}{5}-\frac{1}{5}.\frac{10}{11}+15\%\)
CÁc bn làm chi tiết hộ mik nhé sáng mai mik nộp rồi ai làm đúng mik tick cho
Tìm x:
a, x + 30%x = -1,31
b,\(\left(x-\frac{1}{2}\right):\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)
c, \(\frac{1}{2}x-\frac{3}{4}=\frac{14}{9}.\frac{3}{7}\)
d,\(\frac{-5}{6}-x=\frac{7}{12}+\frac{-1}{3}\)
e,\(\frac{x+3}{-15}=\frac{1}{3}\)
f,\(\left(4,5-2x\right).\left(-1\frac{4}{7}\right)=\frac{11}{14}\)
GIÚP MIK LM TRONG TỐI NAY NHA, MAI MIK PHẢI NỘP RỒI
\(a)x+30\%x=-1,31\)
\(\Leftrightarrow x+\frac{3x}{10}=-1,31\)
\(\Leftrightarrow10x+3x=-13,1\)
\(\Leftrightarrow13x=-13,1\Leftrightarrow x=-\frac{131}{130}\)
\(b)\left(x-\frac{1}{2}\right):\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)
\(\Leftrightarrow\frac{2x-1}{2}.3+\frac{5}{7}=\frac{68}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=\frac{63}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=9\)
\(\Leftrightarrow6x-3=18\)
\(\Leftrightarrow x=\frac{7}{2}\)
\(c)\frac{1}{2}x-\frac{3}{4}=\frac{14}{9}.\frac{3}{7}\)
\(\Leftrightarrow\frac{x}{2}-\frac{3}{4}=\frac{2}{3}\)
\(\Leftrightarrow\frac{x}{2}=\frac{17}{12}\)
\(\Leftrightarrow12x=34\Leftrightarrow x=\frac{17}{6}\)
Bài 1:Tìm x, biết
a, \(\left(4\frac{46}{65}+x\right).1\frac{1}{12}=5,75\) b, \(\frac{5}{4}-\left[\frac{3}{2}.x+0,5\right]=1\frac{1}{4}\)
CÁC BẠN GIÚP MIK NHANH VỚI MAI MIK PHẢI NỘP RỒI.
Dễ mà
a, \(\left(4\frac{46}{65}+x\right).1\frac{1}{2}=5,75\)
\(\left(4\frac{46}{65}+x\right)=5,75:1\frac{1}{2}\)
\(\left(4\frac{46}{65}.x\right)=4\)
\(x=4:4\frac{46}{65}\)
\(x=\frac{130}{153}\)
b tương tự
a,(\(4\frac{46}{65}\)+ x).\(1\frac{1}{12}\)= 5,75
(\(\frac{306}{65}\)+x).\(\frac{13}{12}\)=5,75
(\(\frac{306}{65}\)+x) = 5,75 / \(\frac{13}{12}\)
(\(\frac{306}{65}\)+x) = \(\frac{69}{13}\)
x = \(\frac{69}{13}\)- \(\frac{306}{65}\)
x = \(\frac{3}{5}\)
Tìm x:
a. \(_{_{ }|x|}\)=\(\frac{1}{5}\)
b. \(\frac{x+9}{15}\)=\(\frac{3}{5}\)
c. \(x||\)=0.75
d. \(\frac{x}{169}\)=\(\frac{^{10^4}}{x}\)
e. \(x^3\)(x-5)+3x(x-5)=0
Mong các bn giúp mik nhé!Mai nộp bài rui!huhu
a. \(\frac{1}{5}=0,2\)
\(\Rightarrow|x|=-0,2\)
b.\(\frac{x+9}{15}=\frac{3}{5}\)
\(\frac{9}{15}=\frac{3}{5}\Rightarrow\frac{x+9}{15}=\frac{9}{5}\)
\(\Rightarrow x=0\)
c. \(|x|=0,75=\frac{3}{4}\)
\(|x|=\frac{3}{4}\)
\(|x|=-0,75\)
d.\(\frac{x}{169}=\frac{10^4}{x}\)
\(\frac{x}{169}=\frac{10000}{x}\)
\(\Rightarrow x=-1300\)
\(\frac{x}{3}-\frac{1}{8}=\frac{5}{8}\)
\(3\frac{1}{3}.x-6\frac{3}{4}=3\frac{1}{4}\)
giúp mik nha mai mik kiểm tra rồi
a) \(\frac{x}{3}\)\(-\)\(\frac{1}{8}\)\(=\)\(\frac{5}{8}\)
\(\Rightarrow\) \(\frac{x}{3}\)=\(\frac{5}{8}+\frac{1}{8}\)
\(\Rightarrow\) \(\frac{x}{3}\)\(=\frac{3}{4}\)
\(\Rightarrow\) x=3.3:4
\(\Rightarrow\) x=2,25
Vậy x=2,25
b) \(3\frac{1}{3}\).x-\(6\frac{3}{4}=3\frac{1}{4}\)
\(\Rightarrow\)\(\frac{10}{3}\).x-\(\frac{27}{4}=\frac{13}{4}\)
\(\Rightarrow\) \(\frac{10}{3}\).x=\(\frac{13}{4}+\frac{27}{4}\)
\(\Rightarrow\) \(\frac{10}{3}\).x=10
\(\Rightarrow\) x=\(10\div\frac{10}{3}\)
\(\Rightarrow\) x=3
Vậy x=3
Ủng hộ mik nha mọi người !
Ta có : \(\frac{x}{3}-\frac{1}{8}=\frac{5}{8}\)
\(\Leftrightarrow\frac{x}{3}=\frac{5}{8}-\frac{1}{8}\)
\(\Leftrightarrow\frac{x}{3}=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{2}.\frac{1}{3}=\frac{1}{6}\)
\(\frac{x}{3}-\frac{1}{8}+\frac{5}{8}\)
\(\frac{x}{3}=\frac{5}{8}+\frac{1}{8}=\frac{6}{8}=\frac{3}{4}\)
\(x=\frac{3}{4}.3=\frac{9}{4}\)
\(3\frac{1}{3}x-6\frac{3}{4}=3\frac{1}{4}\)
\(\frac{10}{3}x=3\frac{1}{4}+6\frac{3}{4}=10\)
\(x=10:\frac{10}{3}=3\)