Question

X²-10x-29/1971 + x²-10-17/1973=x²-10x-1971/29+x²-10x-1973/27

Answer 1

\(\dfrac{x^2-10x-29}{1971}+\dfrac{x^2-10x-27}{1973}=\dfrac{x^2-10x-1971}{29}+\dfrac{x^2-10x-1973}{27}\)

\(\Leftrightarrow\left(\dfrac{x^2-10x-29}{1971}-1\right)+\left(\dfrac{x^2-10x-27}{1973}-1\right)=\left(\dfrac{x^2-10x-1971}{29}-1\right)+\left(\dfrac{x^2-10x-1973}{27}-1\right)\)

\(\Leftrightarrow x^2-10x-2000=0\)

\(\Leftrightarrow x^2-10x+25-2025=0\)

\(\Leftrightarrow\left(x-5\right)^2=2025\)

=>x-5=45 hoặc x-5=-45

=>x=50 hoặc x=-40