Ta có : \(\left(x+1\right)\left(2x-3\right)=\left(2x-1\right)\left(x+5\right)\)
=> \(2x^2+2x-3x-3=2x^2-x+10x-5\)
=> \(-x-3=9x-5\)
=> \(10x=2\)
=> \(x=\frac{1}{5}\)
Vậy phương trình có tập nghiệm là \(S=\left\{\frac{1}{5}\right\}\)
Bài 3: Phương trình đưa được về dạng ax + b = 0
Các câu hỏi tương tự
a.(x+5)(2x-1)=(2x-3)(x+1)
b.(x+1)(x+9)=(x+3)(x+5)
c.(3x+5)(2x+1)=(6x-2)(x-3)
d.(x-2)(3x+5)=(2x-4)(x+1)
đ.9x2 -1=(3x+1)(2x-3)
e.(2x+5)(x-4)=(x-5)(4-x)
1) 3 - 2x + 4 + 6x = x + 7 + 3x
2) -6(1,5 - 2x) = 3(-15 + 2x)
3) 3(2x - 5) + 5(x -1) = 4(x + 1)
1) Phương trình dạng ax+b=0
1) 2x+x+12=0
2) x-5=3-x
3)2x-(3-5x)=4(x+3)
4)2x+3/3=5-4x/2
5) x-3/5=6- 1-2x/3
6) 3x-2/6 -5=3-2(x+7)/4
7) 3x-7/2+ x+1/3= -16
8) x- x+1/3=2x+1/5
Câu 1: Giải các phương trình sau:
a) 3x-2(x-3)=0
b) (x+1) (2x-3) = ( 2x -1) (x +5)
c) 2x/ x-1 -x/x+1 =1
d) (2x +3) (3x-5)=0
e) x-2/x+2-3/x-2 = 2(x-11)/ x2
giúp mình với ạ huhu\(^{ }\)
14, giải các PT sau.
1, 4-(x-5)=5(x-3x)
2, 32-4(0,5y-5)=3y+2
3, 19-2(x+11)=5(2x-3)-4(5x-7)
4, 4(x+3)-7x+17=8(5x-1)+166
5, 17-14(x+1)=13-4(x+1)-5(x-3)
6, 5(x+10)2+2x=5x2-3
7, (2x-1)2+5=(2x+3)(2x-3)-x
8, 3(x-2)2+2(x+3)(x-3)=5(x+1)2
14, giải các PT sau.
1, 4-(x-5)=5(x-3x)
2, 32-4(0,5y-5)=3y+2
3, 19-2(x+11)=5(2x-3)-4(5x-7)
4, 4(x+3)-7x+17=8(5x-1)+166
5, 17-14(x+1)=13-4(x+1)-5(x-3)
6, 5(x+10)2+2x=5x2-3
7, (2x-1)2+5=(2x+3)(2x-3)-x
8, 3(x-2)2+2(x+3)(x-3)=5(x+1)2
SN
25 tháng 1 2022 lúc 20:31
4,dfrac{x+1}{3}+dfrac{3left(2x+1right)}{4}dfrac{2x+3left(x+1right)}{6}+dfrac{7+12x}{12}5,dfrac{2x}{3}+dfrac{2x-1}{6}4-dfrac{x}{3}6,dfrac{x-1}{2}+dfrac{x-1}{4}1-dfrac{2left(x-1right)}{3}
Đọc tiếp
4,\(\dfrac{x+1}{3}\)+\(\dfrac{3\left(2x+1\right)}{4}\)=\(\dfrac{2x+3\left(x+1\right)}{6}\)+\(\dfrac{7+12x}{12}\)
5,\(\dfrac{2x}{3}\)+\(\dfrac{2x-1}{6}\)=4-\(\dfrac{x}{3}\)
6,\(\dfrac{x-1}{2}\)+\(\dfrac{x-1}{4}\)=1-\(\dfrac{2\left(x-1\right)}{3}\)
a)5-(x-6)=4(3-2x)
b)2x(x+2)2-8x2=2(x-2)(x2+2x+4)
c)7-(2x+4)=-(x+4)
d)(x-2)3+(3x-1)(3x+1)=(x+1)3
e)(x+1)(2x-3)=(2x-1)(x+5)
f)(x-1)3-x(x+1)2=5x(2-x)-11(x+2)
g)(x-1)-(2x-1)=9-x
h)(x-3)(x+4)-2(3x-2)=(x+4)2
i)x(x+3)2-3x=(x+2)33+11
j)(x+1)(x2-x+1)-2x=x(x+1)(x-1)
giải phương trình sau
1. (2x-3)(2x+3)-4(x+5)^2= -9(1+5x)
2. 2x(x+5)=(x+3)^2+(x-1)^2+20
3.(x+2)^3-(x-2)^3=12x(x-1)-8
5(x+2)-8=7(2x-3)
(2x-1²)-(2-x)(2x-1)=0
6x(x+5)>=3(2x²+5)