\(-3+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{3}}}}\)
\(=-3+\frac{1}{1+\frac{1}{1+\frac{1}{\frac{4}{3}}}}\)
\(=-3+\frac{1}{1+\frac{1}{1+\frac{3}{4}}}\)
\(=-3+\frac{1}{1+\frac{1}{\frac{7}{4}}}\)
\(=-3+\frac{1}{1+\frac{4}{7}}\)
\(=-3+\frac{1}{\frac{11}{7}}\)
\(=-3+\frac{7}{11}\)
\(=-\frac{26}{11}\)
Ta có: \(A=-3+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{3}}}}=-3+\frac{1}{1+\frac{1}{1+\frac{1}{\left(\frac{4}{3}\right)}}}\)
\(=-3+\frac{1}{1+\frac{1}{\frac{4}{4}+\frac{3}{4}}}=-3+\frac{1}{1+\frac{1}{\left(\frac{7}{4}\right)}}\)
\(=-3+\frac{1}{\frac{7}{7}+\frac{4}{7}}=-3+\frac{1}{\left(\frac{11}{7}\right)}=-3+\frac{7}{11}=-\frac{26}{11}\)
Đúng ko ta? ko biết mình có nhìn nhầm chỗ nào ko nx, ngán mấy cái này lắm,rối cả mắt