Question

Tìm x, y, z biết: \(\frac{40x-20y}{5}=\frac{10z-40x}{7}=\frac{20y-10z}{9};\)\(2x+3y+4z=48\)

Answer 1

Từ giả thiết \(\Rightarrow\frac{2.\left(40x-20y\right)}{5}=\frac{2.\left(10z-40x\right)}{7}=\frac{2.\left(2y-10z\right)}{9}\)

\(\Leftrightarrow\frac{80x-40y}{5}=\frac{20z-80x}{7}=\frac{40y-20z}{9}\)