Question

\(\sqrt{x+4\sqrt{x-4}}+\sqrt{x-4\sqrt{x-4}}-2\left(x\ge0\right)\)

Answer 1

Đề là j?

Answer 2

= \(\sqrt{x-4+4\sqrt{x-4}+4}+\sqrt{x-4-4\sqrt{x-4}+4}-2\)

=\(\sqrt{\left(\sqrt{x-4}+2\right)^2}+\sqrt{\left(\sqrt{x-4}-2\right)^2}+2\)

=\(\sqrt{x-4}+2+\sqrt{x-4}-2+2\)

=\(2\sqrt{x-4}+2\)