\(\left(\frac{\sqrt{x}+1}{\sqrt{x}-1}-\frac{\sqrt{x}-1}{\sqrt{x}+1}\right):1-\frac{\sqrt{x}-1}{\sqrt{x}+1}\)
= \(\left(\frac{\left(\sqrt{x}+1\right)\left(\sqrt{x}+1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\frac{\left(\sqrt{x}-1\right)\left(\sqrt{x}-1\right)}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\right):1-\frac{\sqrt{x}-1}{\sqrt{x}+1}\)
= \(\left(\frac{x+2\sqrt{x}+1}{x-1}-\frac{x-2\sqrt{x}+1}{x-1}\right):1-\frac{\left(\sqrt{x}-1\right)\left(\sqrt{x}-1\right)}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\)
=\(\left(\frac{x+2\sqrt{x}+1-x+2\sqrt{x}-1}{x-1}\right):1-\frac{\left(x-2\sqrt{x}+1\right)}{x-1}\)
=\(\frac{4\sqrt{x}}{x-1}-\frac{x-2\sqrt{x}+1}{x-1}\) = \(\frac{4\sqrt{x}-x+2\sqrt{x}-1}{x-1}=\frac{6\sqrt{x}-x-1}{x-1}\)
=\(\frac{\left(6\sqrt{x}-x\right)-1}{x-1}=\frac{\sqrt{x}\left(6-\sqrt{x}+1\right)}{x-1}=\frac{\sqrt{x}\left(7-\sqrt{x}\right)}{x-1}\)
mk ko có chắc là đúng nha >-<!!