Question

Rút gọn

A=\(\dfrac{3}{2+\sqrt{3}}+\dfrac{13}{4-\sqrt{3}}+\dfrac{6}{\sqrt{3}}\)

B=\(\dfrac{x\sqrt{y}-y\sqrt{x}}{\sqrt{xy}}-\dfrac{x-y}{\sqrt{x}—\sqrt{y}}\)với\(x\ne y\)x>0;y>0

C=\(\dfrac{\sqrt{4-2\sqrt{3}}}{\sqrt{6}-\sqrt{2}}\)

D=\((3\sqrt{2}+\sqrt{6})\sqrt{6-3\sqrt{3}}\)

Answer 1

a: \(A=6-3\sqrt{3}+4+\sqrt{3}+2\sqrt{3}=10\)

b: \(B=\sqrt{x}-\sqrt{y}-\sqrt{x}-\sqrt{y}=-2\sqrt{y}\)

c: \(C=\dfrac{\sqrt{3}-1}{\sqrt{6}-\sqrt{2}}=\dfrac{1}{\sqrt{2}}=\dfrac{\sqrt{2}}{2}\)