a)\(\sqrt{\dfrac{4}{9-4\sqrt{5}}}-\sqrt{\dfrac{4}{9+4\sqrt{5}}} \Leftrightarrow \dfrac{\sqrt{4}}{\sqrt{(2-\sqrt{5}})^{2}}-\dfrac{\sqrt{4}}{(2+\sqrt{5})^{2}} \Leftrightarrow \dfrac{2(2+\sqrt{5})}{(\sqrt{5}-2)(2+\sqrt{5})}-\dfrac{2(\sqrt{5}-2)}{(\sqrt{5}-2)(2+\sqrt{5})} \Leftrightarrow \dfrac{4+2\sqrt{5}-(2\sqrt{5}-4)}{4-5} \Leftrightarrow \dfrac{8}{-1} = -8\)b)\(\dfrac{\sqrt{8-4\sqrt{3}}}{\sqrt{2}} =\dfrac{\sqrt{2}\sqrt{8-4\sqrt{3}}}{\sqrt{2}\sqrt{2}} =\dfrac{\sqrt{16-8\sqrt{3}}}{2} =\dfrac{\sqrt{(2-2\sqrt{3})^{2}}}{2} =\dfrac{2\sqrt{3}-2}{2} =\dfrac{2(\sqrt{3}-1)}{2} =\sqrt{3}-1\)c)\(\sqrt{14-8\sqrt{3}}-\sqrt{24-12\sqrt{3}} =\sqrt{2}\sqrt{7-4\sqrt{3}}-\sqrt{2}\sqrt{12+6\sqrt{3}} =\sqrt{2}(\sqrt{(4-\sqrt{3})^{2}}-\sqrt{(3+\sqrt{3})^{2}}) =\sqrt{2}((4-\sqrt{3})-(3+\sqrt{3})) =\sqrt{2}(1-2\sqrt{3}) =\sqrt{2}-2\sqrt{6}\)