\(\left(\dfrac{1}{2}x-\dfrac{2}{3}\right)-\left(\dfrac{1}{3}x-1\right)=\left(x-3\right)-\left(x-1\right)\)
\(\Leftrightarrow\dfrac{1}{2}x-\dfrac{2}{3}-\dfrac{1}{3}x+1=x-3-x+1\)
\(\Leftrightarrow\dfrac{1}{2}x-\dfrac{2}{3}-\dfrac{1}{3}x=-3\)
\(\Leftrightarrow\dfrac{x}{6}-\dfrac{2}{3}=-3\)
\(\Leftrightarrow x-4=-18\)
\(\Leftrightarrow x=-18+4\)
\(\Leftrightarrow x=-14\)
Vậy \(x=-14\)
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