a) Xét hình thang ABCD(AB//CD) có
E∈AD(gt)
G∈BC(gt)
EG//AB//CD(gt)
Do đó: \(\dfrac{AE}{ED}=\dfrac{BG}{GC}\)(Định lí Ta lét)
\(\Leftrightarrow\dfrac{BG}{GC}=\dfrac{2}{5}\)
\(\Leftrightarrow\dfrac{BG}{GC}+1=\dfrac{2}{5}+1\)
\(\Leftrightarrow\dfrac{BC}{GC}=\dfrac{7}{5}\)
hay \(\dfrac{CG}{BC}=\dfrac{5}{7}\)