Question

Giải phương trình:

(x-2/2)-(x-2/6)+(2-x/3)=5

 

Answer 1

\( \dfrac{x-2}{2}-\dfrac{x-2}{6}+\dfrac{2-x}{3}=5 \\ \Leftrightarrow 3(x-2)-(x-2)+2(2-x)=5 \\ \Leftrightarrow 3x-6-x+2+4-2x = 5 \Leftrightarrow 0x = 5 \)

Vậy PTVN.

Answer 2

\(\dfrac{x-2}{2}-\dfrac{x-2}{6}+\dfrac{2-x}{3}=5\\ \Leftrightarrow\dfrac{x-2}{2}-\dfrac{x-2}{6}-\dfrac{x-2}{3}=5\\ \Leftrightarrow\dfrac{3\left(x-2\right)}{6}-\dfrac{x-2}{6}-\dfrac{2\left(x-2\right)}{3}=\dfrac{30}{6}\\ \Leftrightarrow3\left(x-2\right)-\left(x-2\right)-\left(2x-2\right)=30\\ \Leftrightarrow\left(x-2\right)\left(3-1-2\right)=30\\ \Leftrightarrow\left(x-2\right).0=30\)

=> PT vô nghiệm

Answer 3

x−2/2−x−2/6+2−x/3=5⇔3(x−2)−(x−2)+2(2−x)=5⇔3x−6−x+2+4−2x=5⇔0x=5