ĐKXĐ: \(x\ge\frac{1}{5}\)
\(\Leftrightarrow2x^2+x-3+\left(2-\sqrt[3]{9-x}\right)+\left(2x-\sqrt{5x-1}\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(2x+3\right)+\frac{x-1}{4+2\sqrt[3]{9-x}+\sqrt[3]{\left(9-x\right)^2}}+\frac{\left(x-1\right)\left(4x-1\right)}{2x+\sqrt{5x-1}}=0\)
\(\Leftrightarrow\left(x-1\right)\left(2x+3+\frac{1}{4+2\sqrt[3]{9-x}+\sqrt[3]{\left(9-x\right)^2}}+\frac{4x-1}{2x+\sqrt{5x-1}}\right)=0\)
\(\Leftrightarrow x=1\) (ngoặc to luôn dương)
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