Question

Giải phương trình 

4x^3-16x=0

Answer 1

\(4x^3-16x=0\)

\(\Leftrightarrow4x\cdot\left(x^2-4\right)=0\)

\(\Leftrightarrow4x\cdot\left(x-2\right)\cdot\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}4x=0\\x-2=0\\x+2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)

Answer 2

\(\Leftrightarrow\)\(4x(x^{2}-4)=0\)

\(\Leftrightarrow\)\(\left[\begin{array}{} 4x=0\\ x^{2}-4=0 \end{array} \right.\)

\(\Leftrightarrow\)\(\left[\begin{array}{} x=0\\ x=2,x=-2 \end{array} \right.\)

Answer 3

Ta có: \(4x^3-16x=0\)

\(\Leftrightarrow x\left(x-2\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)