Question

G

Answer 1

\(\Leftrightarrow\left(x-3\right)\left(\sqrt{x^2+4}-\left(x+3\right)\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x^2+4=x^2+6x+9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{5}{6}\end{matrix}\right.\)