Question

\(\frac{5}{2}\)-x +\(\frac{4}{5}\)= \(\frac{2}{3}\)+\(\frac{4}{7}\)

Answer 1

\(\dfrac{5}{2} - x + \dfrac{4}{5} = \dfrac{2}{3} + \dfrac{4}{7}\\ \Leftrightarrow \dfrac{{33}}{{10}} - x = \dfrac{{26}}{{21}}\\ \Leftrightarrow - x = \dfrac{{26}}{{21}} - \dfrac{{33}}{{10}}\\ \Leftrightarrow - x = - \dfrac{{433}}{{210}}\\ \Leftrightarrow x = \dfrac{{443}}{{210}} \)

Vậy \(x = \dfrac{443}{210}\)

Answer 2

\(\frac{5}{2}-x+\frac{4}{5}=\frac{2}{3}+\frac{4}{7}\)

=> \(\frac{33}{10}-x=\frac{26}{21}\)

=> \(x=\frac{33}{10}-\frac{26}{21}\)

=> \(x=\frac{433}{210}\)

Vậy \(x=\frac{433}{210}.\)

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