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Đặt \(x^2-3x+2=t\Rightarrow2x^2-6x+1=2t-3\)
\(\frac{4}{t}-\frac{3}{2t-3}+1=0\)
\(\Leftrightarrow8t-12-3t+t\left(2t-3\right)=0\)
\(\Leftrightarrow2t^2+2t-12=0\Rightarrow\left[{}\begin{matrix}t=2\\t=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x^2-3x+2=2\\x^2-3x+2=-3\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x^2-3x=0\\x^2-3x+5=0\end{matrix}\right.\)
\(\frac{4}{x^2-3x+2}-\frac{3}{2x^2-6x+1}+1=0\)
\(\frac{1}{x-1}+\frac{2}{x-2}+\frac{3}{x-3}=\frac{6}{x-6}\)
\(1+\frac{45}{y^2-8y+16}=\frac{14}{y-4}\)
\(\frac{5}{x-1}-\frac{4}{3-6x+3x^2}=3\)
\(\frac{2x-5}{x-5}=3\)
\(\frac{x^2-12}{x}=x+\frac{3}{2}\)
\(\frac{\left(x^2-4\right)-\left(3x-6\right)}{x-2}=0\)
\(\frac{8}{2x+1}=2x-1\)
Giải phương trình :a) \(x^3+\frac{x^3}{\left(x-1\right)^3}+\frac{3x^2}{x-1}-2=0\)
b) \(\frac{1}{x^2-3}+\frac{1}{2x^2-9}+\frac{1}{3x^2-6}=\frac{1}{6x^2-18}\)
giải phương trình
\(\left(\frac{3}{2x+1}+2\right).\left(5x-2\right)=\frac{5x-2}{2x+1}\)
\(\frac{-2x-1}{2-3x}-\frac{5}{2+3x}=\frac{6x^2}{9x^2-4}\)
\(\frac{x}{x-1}-\frac{2}{x+1}=\frac{x^2+11}{x^2-1}\)
\(1.\frac{1}{x^2-2x+2}+\frac{2}{x^2-2x+3}=\frac{6}{x^2-2x+4}
\)
2.\(\frac{2x^4}{\left(x+1\right)^2}-\frac{5x^2}{x+1}+2=0\)
3.\(\left(x+\frac{1}{x}\right)^2-6\left(x+\frac{1}{x}\right)+8=0\)
4.\(\left(x^2+\frac{1}{x^2}\right)-4\left(x+\frac{1}{x}\right)+6=0\)
5.\(\frac{2x}{3x^2-x+2}-\frac{7x}{3x^2+5x+2}=1\)
a. \(\frac{5x}{3x+2}\)+1=\(\frac{-6x}{x+1}\)
b.\(\frac{x+3}{x+1}\)+\(\frac{x-2}{x}\)=2
c.\(\frac{3x-2}{x+7}\)=\(\frac{6x+1}{2x-3}\)
d.\(\frac{1}{2x-3}\)-\(\frac{3}{x\left(2x-3\right)}\)=\(\frac{5}{x}\)
e.\(\frac{x+1}{x-2}\)+\(\frac{x-1}{x+2}\)=\(\frac{2\left(x^2+2\right)}{x^2-4}\)
Giái phương trình :
a,\(\frac{6x+1}{x^2-7x+10}+\frac{5}{x-2}=\frac{3}{x-5}\)
b,\(\frac{2}{x^2-4}-\frac{x-1}{x\left(x-2\right)}+\frac{x-4}{x\left(x+2\right)}=0\)
c,\(\frac{1}{3-x}-\frac{1}{x+1}=\frac{x}{x-3}-\frac{\left(x-1\right)^2}{x^2-2x-3}\)
d,\(\frac{2}{x+2}-\frac{2x^2+16}{x^3+8}=\frac{5}{x^2-2x+4}\)
Giải bài tập :
a) \(\frac{3x+2}{2}\) - \(\frac{3x+1}{6}\) = \(\frac{5}{3}\) + 2x
b) \(\frac{x+4}{5}\) - x + 4 = \(\frac{x}{3}\) - \(\frac{x-2}{2}\)
c) \(\frac{4x+3}{5}\) - \(\frac{6x-2}{7}\) = \(\frac{5x+4}{3}\) + 3
d) \(\frac{5x+2}{6}\) - \(\frac{8x-1}{3}\) = \(\frac{4x-2}{5}\) - 5
e) \(\frac{2x-1}{5}\) - \(\frac{x-2}{7}\) = \(\frac{x+7}{15}\)
f) \(\frac{1}{4}\)(x + 3) = 3 - \(\frac{1}{2}\)(x + 1) - \(\frac{1}{3}\)(x - 2)
Các cậu ơi, ai giải được thì giải giúp tớ với. Tớ đang cần rất gấp ạ, tớ cảm ơn các cậu trước nha ^^.
Giai phuong trinh:
a)\(\frac{4+9x}{9x^21}=\frac{3}{3x+1}-\frac{2}{1-3x}\)
b)\(\frac{2x-3}{x+1}+\frac{x^2-5x+10}{\left(x+1\right)\left(x-3\right)}=\frac{3x-5}{x-3}\)
c)\(\frac{x\left(x+4\right)}{2x-3}=\frac{x^2+4}{2x-3}+1-\frac{2}{3-2x}\)
d)\(\frac{1}{x+2}+\frac{x}{x-3}=1-\frac{5x}{\left(x+2\right)\left(3-x\right)}-\frac{1}{x+2}\)