Gọi \(\left\{{}\begin{matrix}n_{CH3OH}:a\left(mol\right)\\n_{C2H5OH}:b\left(mol\right)\end{matrix}\right.\)
\(CH_3OH+\frac{5}{2}O_2\rightarrow CO_2+2H_2O\)
a__________2,5a___a_______2a
\(C_2H_5OH+3O_2\rightarrow2CO_2+3H_2O\)
b_________3b______2b________3b
\(\Rightarrow n_{CO2}=\frac{8,96}{22,4}=0,4\left(mol\right)\)
Giải hệ PT:
\(\left\{{}\begin{matrix}32a+46b=11\\a+2b=0,4\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=0,2\\b=0,1\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\%m_{CH3OH}=\frac{0,2.32}{11}.100\%=58,18\%\\\%m_{C2H6OH}=100\%-58,18\%=41,82\%\end{matrix}\right.\)
Ta có:
\(n_{O2}=0,2.2,5+0,1.3=0,8\left(mol\right)\)
\(\Rightarrow V_{O2}=0,8.22,4=17,92\left(l\right)\)
\(n_{H2O}=0,2.2+0,1.3=0,7\left(mol\right)\)
\(\Rightarrow m_{H2O}=0,7.18=12,6\left(g\right)\)