Question

Điều Chế 230kg rượu cần bao nhiêu glucozo biết hiệu suất phản ứng là 60%

Answer 1

\(C_6H_{12}O_6\underrightarrow{t^o,xt}2C_2H_5OH+2CO_2\)

\(n_{C_2H_5OH}=\dfrac{230}{46}=5\left(kmol\right)\)

Theo PT: \(n_{C_6H_{12}O_6\left(LT\right)}=\dfrac{1}{2}n_{C_2H_5OH}=2,5\left(kmol\right)\)

Mà: H = 60%

\(\Rightarrow n_{C_6H_{12}O_6\left(TT\right)}=\dfrac{2,5}{60\%}=\dfrac{25}{6}\left(kmol\right)\)

\(\Rightarrow m_{C_6H_{12}O_6\left(TT\right)}=\dfrac{25}{6}.180=750\left(kg\right)\)

Answer 2

\(n_{C_2H_5OH}=\dfrac{230}{46}=5\left(mol\right)\)

PTHH :

\(C_6H_{12}O_6\underrightarrow{lenmen}2C_2H_5OH+2CO_2\uparrow\)

2,5                        0,5 

\(m_{C_6H_{12}O_6\left(lt\right)}=2,5.180=450\left(g\right)\)

\(m_{C_6H_{12}O_6\left(tt\right)}=\dfrac{450.100}{60}=750\left(g\right)\)