Question

Chứng minh đẳng thức:

(\(1-\frac{4}{a}\))(\(\frac{\sqrt{a}-1}{\sqrt{a}+2}\)-\(\frac{\sqrt{a}+1}{\sqrt{a}-2}\)) =\(\frac{-6}{\sqrt{a}}\) với a > 0 và a ≠ 4

Answer 1

\(\left(\frac{a-4}{a}\right)\left(\frac{\sqrt{a}-1}{\sqrt{a}+2}-\frac{\sqrt{a}+1}{\sqrt{a}-2}\right)=\left(\frac{a-4}{a}\right)\left(\frac{\left(\sqrt{a}-1\right)\left(\sqrt{a}-2\right)-\left(\sqrt{a}+1\right)\left(\sqrt{a}+2\right)}{\left(\sqrt{a}+2\right)\left(\sqrt{a}-2\right)}\right)\)

\(=\left(\frac{a-4}{a}\right)\left(\frac{a-3\sqrt{a}+2-a-3\sqrt{a}-2}{a-4}\right)\)

\(=\frac{-6\sqrt{a}}{a}=\frac{-6}{\sqrt{a}}\)