Bài 8: Tính chất của dãy tỉ số bằng nhau
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TP
12 tháng 11 2021 lúc 21:16
cho a+b+c+d khác 0 vàti\(\dfrac{b+c+d-a}{a}=\dfrac{c+d+a-b}{b}=\dfrac{d+a+b-c}{c}=\dfrac{a+b+c-d}{d}P=\left(1+\dfrac{b}{a}\right)\left(1+\dfrac{c}{b}\right)\left(1+\dfrac{c}{d}\right)\left(1+\dfrac{a}{d}\right)\)tính P
giúp mk với ạ , xin cảm ơn
1. Cho dfrac{a}{b} dfrac{c}{d} c/m
a) (2a+3c) . (2b-3d) (2a- 3c) . (2b+3d)
b) dfrac{left(a^2+cright)^2}{left(b+dright)^2} dfrac{left(a-cright)^2}{left(b-dright)^2}
c)dfrac{a^3+b^3}{c^3+d^3} dfrac{a^3-b^3}{c^3-d^3}
d) dfrac{a^{2018}-b^{2018}}{a^{2018}+b^{2018}} dfrac{c^{2018}-d^{2018}}{c^{2018}+d^{2018}}
HELP ME ~ !!!
Đọc tiếp
1. Cho \(\dfrac{a}{b}\) = \(\dfrac{c}{d}\) c/m
a) (2a+3c) . (2b-3d) = (2a- 3c) . (2b+3d)
b) \(\dfrac{\left(a^2+c\right)^2}{\left(b+d\right)^2}\) = \(\dfrac{\left(a-c\right)^2}{\left(b-d\right)^2}\)
c)\(\dfrac{a^3+b^3}{c^3+d^3}\) = \(\dfrac{a^3-b^3}{c^3-d^3}\)
d) \(\dfrac{a^{2018}-b^{2018}}{a^{2018}+b^{2018}}\) = \(\dfrac{c^{2018}-d^{2018}}{c^{2018}+d^{2018}}\)
HELP ME >~< !!!
Cho tỉ lệ thức \(\dfrac{a}{b}=\dfrac{c}{d}\). Hãy chứng minh rằng :
\(\dfrac{a}{a+b}=\dfrac{c}{c+d}\)
\(\dfrac{a+2c}{b+2d}=\dfrac{a-2c}{b-2d}\)
\(\dfrac{a^2+2b^2}{c^2+2d^2}=\dfrac{a^2-2b^2}{c^2-2d^2}\)
\(\dfrac{ab}{cd}=\dfrac{\left(a+b\right)^2}{\left(c+d\right)^2}\)
cho abc khác 0 và dfrac{a-b+c}{c}dfrac{b+c-a}{a}dfrac{a+c-b}{b} Tính Pleft(1+dfrac{b}{a}right)left(1+dfrac{c}{b}right)left(1+dfrac{a}{c}right) giúp mik nha! help me
Đọc tiếp
cho abc khác 0 và \(\dfrac{a-b+c}{c}=\dfrac{b+c-a}{a}=\dfrac{a+c-b}{b}\) Tính P\(=\left(1+\dfrac{b}{a}\right)\left(1+\dfrac{c}{b}\right)\left(1+\dfrac{a}{c}\right)\) giúp mik nha! help me =='
OY
12 tháng 11 2021 lúc 17:39
Cho \(\dfrac{b+c-5}{a}=\dfrac{a+c+2}{b}=\dfrac{a+b+3}{c}=\dfrac{1}{a+b+c}\left(a,b,c\ne0,a+b+c\ne0\right)\)
Tính \(\left(a-3b\right)\left(b-c\right)\left(3c-a\right)\)
Ai giúp mik đi, mik cho 5 coin
Cho \(\dfrac{b+c-3a}{a}=\dfrac{a+c-3b}{b}=\dfrac{a+b-3c}{c}\)
Tính: M=\(\dfrac{\left(a+b\right)\left(b+c\right)\left(c+a\right)}{abc}\)
1.TÌm x,y,z biết
a.2009-\(\left|x-2009\right|\)=x
b.\(\left(2x-1\right)^{2008}+\left(y-\dfrac{2}{5}\right)^{2008}+\left|x+u-z\right|\)=0
2.Tìm các số a,b,c biết
\(\dfrac{3a-2b}{5}=\dfrac{2c-5a}{3}=\dfrac{5b-3c}{2}\)
và a+b+c = -50
1. Cho \(\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{d}\). Chứng minh rằng \(\left(\dfrac{a+b+c}{b+c+d}\right)^3=\dfrac{a}{d}\)
2. Cho \(\dfrac{a}{2003}=\dfrac{b}{2004}=\dfrac{c}{2005}\). Chứng minh rằng \(4\left(a-b\right)\left(b-c\right)=\left(c-a\right)^2\)
Cho a, b, c thỏa mãn \(\dfrac{a}{2009}=\dfrac{b}{2010}=\dfrac{c}{2011}\)
Tính \(M=\left(a-b\right)\left(b-c\right)-c^2-2ac-a^2\)