Question

Bài 11: Tìm x, y, z:

a) \(x=4y=0,4\left(y+z\right)\) và \(x+y+z=280\)

Giúp mk vs, ai nhanh mk sẽ tick

Answer 1

\(\dfrac{y}{0,4}\) chuyển thành y.\(\dfrac{5}{2}\)=\(\dfrac{y+z}{4}\)

suy ra \(\dfrac{x}{4}\)=y=\(\dfrac{y+z}{10}\) y= \(\dfrac{y+z}{10}\) suy ra y=\(\dfrac{y}{10}+\dfrac{z}{10}\) suy ra \(\dfrac{9}{10}y=\dfrac{1}{10}z\) suy ra \(y=\dfrac{1}{9}z\) hay z=9y x+y+z=4y+y+9y=14y 14y=280 y=280:14=20 x=20.4=80 z=280-(20+80)=180 Tick mk nha

Answer 2

Bài 11: Tìm x, y, z:

a) $x=4y=0,4\left(y+z\right)$ và $x+y+z=280$