Question

a) (x^2 +2x+1)-x-1 phần 3=6(x+1)^2-5x-5 phần 6

b)(x-1)-2(x-1) phần 3=1 + (2x-2) phần 2

c)(x-2)^2=(2x-3)^2-(x+1)^2

d)(x-2)(x^2-3x+5)=x^2-2x^2

Answer 1

b: \(\left(x-1\right)-\dfrac{2\left(x-1\right)}{3}=1+\dfrac{\left(2x-2\right)}{2}\)

=>\(\dfrac{1}{3}\left(x-1\right)-\left(x-1\right)=1\)

=>\(\dfrac{-2}{3}\left(x-1\right)=1\)

=>\(x-1=1:\dfrac{-2}{3}=\dfrac{-3}{2}\)

=>\(x=-\dfrac{3}{2}+1=-\dfrac{1}{2}\)