Question

2,8-5.(x-10)=\(\dfrac{-3}{4}\)

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Answer 1

\(2,8-5.\left(x-10\right)=\dfrac{-3}{4}\)
\(5.\left(x-10\right)=2,8-\dfrac{-3}{4}\)
\(5.\left(x-10\right)=\dfrac{14}{5}+\dfrac{3}{4}\)
\(5.\left(x-10\right)=\dfrac{56}{20}+\dfrac{15}{20}\)
\(5.\left(x-10\right)=\dfrac{71}{20}\)
\(x-10=\dfrac{71}{20}:5\)
\(x-10=\dfrac{71}{20}.\dfrac{1}{5}\)
\(x-10=\dfrac{71}{100}\)
\(x=\dfrac{71}{100}+10\)
\(x=\dfrac{71}{100}+\dfrac{1000}{100}\)
\(x=\dfrac{1071}{100}\)
Vậy \(x=\dfrac{1071}{100}\)

Answer 2

\(2,8-5\left(x-10\right)=-\dfrac{3}{4}\)

\(\dfrac{14}{5}-5\left(x-10\right)=-\dfrac{3}{4}\)

\(5\left(x-10\right)=\dfrac{14}{5}-\left(-\dfrac{3}{4}\right)\)

\(5\left(x-10\right)=\dfrac{71}{20}\)

\(x-10=\dfrac{71}{100}\)

\(x=10+\dfrac{71}{100}\)

\(x=\dfrac{1071}{100}\)