Question

1. Áp dụng quy tắc khai phương 1 thương, tính:

\(\frac{3\sqrt{128}}{\sqrt{2}}\)

2. Tính:

a.

b. (\(5\sqrt{48}-3\sqrt{27}+2\sqrt{12}\)):\(\sqrt{3}\)

c. \(\sqrt{3-\sqrt{5}}-\sqrt{3+\sqrt{5}}\)

d. \(\sqrt{4+\sqrt{7}}-\sqrt{4-\sqrt{7}}-\sqrt{2}\)

e. \(\left(\sqrt{6}-\sqrt{2}\right)\sqrt{2+\sqrt{3}}\)

f. \(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)

Answer 1

1.\(\frac{3\sqrt{128}}{\sqrt{2}}=\frac{\sqrt{9.128}}{\sqrt{2}}=\sqrt{\frac{1152}{2}}=\sqrt{576}=24\)