a, \(A=\left\{0;\dfrac{1}{2};2;-\dfrac{1}{2}\right\}\)
b, \(B=\left\{2;3;4;5\right\}\)
22:
a: (2x-x^2)(2x^2-3x-2)=0
=>x(2-x)(2x^2-4x+x-2)=0
=>-x(x-2)^2*(2x+1)=0
=>x=0;x=2;x=-1/2
=>A={0;2;-1/2}
b: 3<n^2<30
=>n^2 thuộc {4;9;16;25}
mà n>0
nên n thuộc {2;3;4;5}
=>B={2;3;4;5}