Bài 2
a, đk : x > = -2
\(\left[{}\begin{matrix}5x=x+2\\5x=-x-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=-\dfrac{1}{3}\end{matrix}\right.\left(tm\right)\)
b, đk : x > = 3/2
\(\left[{}\begin{matrix}-3x=2x-3\\-3x=3-2x\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{5}\left(ktm\right)\\x=-3\left(ktm\right)\end{matrix}\right.\)
c, đk : x > = - 3
\(\left[{}\begin{matrix}x+4=x+3\\x+4=-x-3\end{matrix}\right.\Leftrightarrow2x=1\Leftrightarrow x=\dfrac{1}{2}\)(tm)
d, đk : x > = 0 \(\left[{}\begin{matrix}3-x=2x\\3-x=-2x\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\left(tm\right)\\x=-3\left(ktm\right)\end{matrix}\right.\)
Đúng 2
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