Câu 3:
\(\dfrac{a}{b}=\dfrac{c}{d}=\dfrac{-10a}{-10b}=\dfrac{10c}{10d}=\dfrac{-10a+c}{-10b+d}=\dfrac{a+10c}{b+10d}\)
Chọn C
Câu 4:
\(f\left(-1\right)=2+1=3\left(đúng\right)\\ f\left(0\right)=0+1=1\left(đúng\right)\\ f\left(\dfrac{1}{2}\right)=-2\cdot\dfrac{1}{2}+1=-1+1=0\left(đúng\right)\)
Vậy chọn D