c. \(\sqrt{\dfrac{0,25}{9}}=\dfrac{\sqrt{0,25}}{\sqrt{9}}=\dfrac{0,5}{3}=\dfrac{1}{6}\)
d1. \(\sqrt{\dfrac{8,1}{1,6}}=\dfrac{\sqrt{8,1}}{\sqrt{1,6}}=\dfrac{9}{4}\)
d2. \(\dfrac{\sqrt{6^5}}{\sqrt{2^3.3^5}}=\sqrt{\dfrac{6^5}{2^3.3^5}}=\sqrt{\dfrac{7776}{1944}}=\sqrt{4}=2\)
c) \(\sqrt{\dfrac{0,25}{9}}=\sqrt{\dfrac{1}{36}}=\dfrac{1}{6}\)
d) \(\sqrt{\dfrac{8,1}{1,6}}=\sqrt{\dfrac{81}{16}}=\dfrac{9}{4}\)
d') \(\dfrac{\sqrt{6^5}}{\sqrt{2^3.3^5}}=\dfrac{\sqrt{6^5}}{\sqrt{3^2}\sqrt{6^3}}=\dfrac{\sqrt{6^2}}{\sqrt{3^2}}=\dfrac{6}{3}=2\)
Do có 2 câu d nên mik đặt là ''d1'' và ''d2'' nha, bn thông cảm .
\(\sqrt{\dfrac{0.25}{9}}\)=\(\dfrac{1}{6}\)
\(\sqrt{\dfrac{8,1}{1,6}}\)=\(\dfrac{9}{4}\)
\(\sqrt{\dfrac{6^5}{2^3.3^5}}\)=2