\(\sqrt{\frac{\left(\sqrt{3}+1\right)^2}{4}=}?\)
\(\dfrac{\sqrt{3}+1}{2}\). \(\dfrac{\sqrt{3}+1}{4}\). \(\sqrt{3}+1\). \(-\dfrac{\sqrt{3}+1}{2}\). Hướng dẫn giải:\(\sqrt{\dfrac{\left(\sqrt{3}+1\right)^2}{4}}=\dfrac{\sqrt{\left(\sqrt{3}+1\right)^2}}{\sqrt{4}}=\dfrac{\left|\sqrt{3}+1\right|}{2}=\dfrac{\sqrt{3}+1}{2}\)
