Cho biết \(\sqrt{3}x+\sqrt{3}=\sqrt{12}+\sqrt{27}\). Hỏi x = ?
x = 2. x = 3. x = 4. x = 5. Hướng dẫn giải:\(\sqrt{3}x+\sqrt{3}=\sqrt{12}+\sqrt{27}\)\(\Leftrightarrow\sqrt{3}x=\sqrt{12}+\sqrt{27}-\sqrt{3}\)\(\Leftrightarrow x=\dfrac{\sqrt{12}+\sqrt{27}-\sqrt{3}}{\sqrt{3}}\)
\(\Leftrightarrow x=\sqrt{\dfrac{12}{3}}+\sqrt{\dfrac{27}{3}}-\sqrt{\dfrac{3}{3}}\)\(\Leftrightarrow x=\sqrt{4}+\sqrt{9}-\sqrt{1}\)\(\Leftrightarrow x=2+3-1=4\).
