\((x+1)^2-4(x+1)+4\\=(x+1)^2-2\cdot(x+1)\cdot2+2^2\\=[(x+1)-2]^2\\=(x+1-2)^2\\=(x-1)^2\)
(x + 1)² - 4(x + 1) + 4
= x² + 2x + 1 - 4x - 4 + 4
= x² - 2x + 1
= (x - 1)²
Giải phương trình:
a)(x+1/x-2)^2+x+1/x-4-3(2x-4/x-4)^2=0
b)4/x^2(x+1)^2-4(1/x-1/x+1)+1=0
1) (3x-2)/3-2=(4x+1)/42) (x-3)/4+(2x-1)/3=(2-x)/63) 1/2 (x+1)+1/4 (x+3)=3-1/3 (x+2)4) (x+4)/5-x+4=x/3-(x-2)/25) (4-5x)/6=2(-x+1)/2 6) (-(x-3))/2-2=5(x+2)/4 7)2(2x+1)/5-(6+x)/3=(5-4x)/158) (7-3x)/2-(5+x)/5=1 9)(x-1)/2+3(x+1)/8=(11-5x)/310)(3+5x)/5-3=(9x-3)/4
8(x+ 1/x)^2 +4(x^2 + 1/x^2) -4(x^2+ 1/x^2)(x+ 1/x)^2 = (x+4)^2
8(x+1/x)^2+4(x^2+1/x^2)^2-4(x^2+1/x^2)(x+1/x)^2=(x+4)^2
8(x + 1/x)^2 +4(x^2 + 1/x^2)^2 -4(x^2 + 1/x^2)(x + 1/x)^2=(x + 4)^2
bài 1 rút gọn biểu thức
a) (2x-5)^2-4x(x+3)
b) (x-2)^3 -6(x+4)(x-4)-(x-2)(x^2+2x+4)
c)(x-1)^2-2(x-1)(x+2)+(x+2)^2+5(2x-3)
bài 2 rút gọn biểu thức
a)(2-3x)^2-5x(x-4)+4(x-1)
b)(3-x)(x^2+3x+9)+(x-3)^3
c)(x-4)^2(x+4)-(x-4)(x+4)^2+3(x^2-16)
(2x-1/x)^4
(2x^2-1/x)^4
[(2x)^2-1/x]^4
[(2x)^2-1/x^2]^4
(2x-1/x)^4
(2x^2-1/x)^4
[(2x)^2-1/x]^4
[(2x)^2-1/x^2]^4
(2x-1/x)^4
(2x^2-1/x)^4
[(2x)^2-1/x]^4
[(2x)^2-1/x^2]^4
(2x-1/x)^4
(2x^2-1/x)^4
[(2x)^2-1/x]^4
[(2x)^2-1/x^2]^4
