Question

Tính:

A = \(\sqrt{\dfrac{25}{3-2\sqrt{2}}}\)

B = \(\sqrt{\dfrac{a^4b^3}{a^2b-ab}}\left(a>1;b>0\right)\)

Answer 1

`A=\sqrt{25/[3-2\sqrt{2}]}`

`A=\sqrt{[25(3+2\sqrt{2})]/[9-8]}`

`A=5\sqrt{3+2\sqrt{2}}`

___________

`B=\sqrt{[a^4 b^3]/[a^2 b-ab]}`       `(a > 1;b > 0)`

`B=\sqrt{[ab.a^3 b^2]/[ab(a-1)]}`

`B=ab\sqrt{a/[a-1]}`