Giải:
a) \(A=\left(\sqrt{3}-2\right)^2\left(\sqrt{3}+2\right)^2\)
\(\Leftrightarrow A=\left[\left(\sqrt{3}\right)^2-2^2\right]^2\)
\(\Leftrightarrow A=\left(3-4\right)^2\)
\(\Leftrightarrow A=\left(-1\right)^2=1\)
Vậy ...
b) \(B=\left(\sqrt{5}+2\right)^2\)
\(\Leftrightarrow B=\left(\sqrt{5}\right)^2+2.\sqrt{5}.2+2^2\)
\(\Leftrightarrow B=5+4\sqrt{5}+4\)
\(\Leftrightarrow B=9+4\sqrt{5}\)
Vậy ...