Nhận xét \(\left\{{}\begin{matrix}|2x-2011|\ge0\forall x\\\left(3y+2012\right)^{2012}\ge0\forall y\end{matrix}\right.\)
Đẳng thức xảy ra khi \(\left\{{}\begin{matrix}2x-2011=0\\3y+2012=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{2011}{2}\\y=-\dfrac{2012}{3}\end{matrix}\right.\)
\(\left|2x-11\right|+\left(3y+2012\right)^{2012}=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x-11=0\\3y+2012=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{11}{2}\\y=-\dfrac{2012}{3}\end{matrix}\right.\)
`=> {(2x - 2011 = 0), ((3y + 2012)^2012 = 0):}`
`=> {(x = 2011/2), (y = -2012/3):}`.