\(\dfrac{3}{4}-\left\{2-3.\left[\dfrac{7}{2}-\left(\dfrac{2}{3}\right)^2\right]\right\}=\dfrac{3}{4}-\left\{2-3.\left[\dfrac{7}{2}-\dfrac{4}{9}\right]\right\}=\dfrac{3}{4}-\left\{2-3.\dfrac{55}{18}\right\}=\dfrac{3}{4}-\left\{2-\dfrac{55}{6}\right\}=\dfrac{3}{4}-\left\{\dfrac{-43}{6}\right\}=\dfrac{95}{12}\)
\(\dfrac{3}{4}-\left\{2-3.\left[\dfrac{7}{2}-\left(\dfrac{2}{3}\right)^2\right]\right\}\\ =\dfrac{3}{4}-\left[2-3.\left(\dfrac{7}{2}-\dfrac{4}{9}\right)\right]\\ =\dfrac{3}{4}-\left(2-3\cdot\dfrac{55}{18}\right)\\ =\dfrac{3}{4}-\left(2-\dfrac{55}{6}\right)\\ =\dfrac{3}{4}-\left(-\dfrac{43}{6}\right)\\ =\dfrac{3}{4}+\dfrac{43}{6}\\ =\dfrac{95}{12}\)
`@` `\text {Ans}`
`\downarrow`
`b)`
`3/4 - {2 - 3*[7/2 - (2/3)^2]}`
`= 3/4 - [2 - 3*(7/2 - 4/9)]`
`= 3/4 - (2 - 3*55/18)`
`= 3/4 - (2 - 55/6)`
`= 3/4 - (-43/6)`
`= 95/12`
3/4 - {2 - 3.[7/2 - (2/3)²]}
= 3/4 - [2 - 3.(7/2 - 4/9)
= 3/4 - (2 - 3.55/18)
= 3/4 - (2 - 55/6)
= 3/4 + 43/6
= 95/12
